Coding Decoding: SSC CGL Practice Questions

Q. 1 If “FILE” is represented by 8357 and “SINK” is represented by 9364, what would be the code for “NIKE”?
Check Solution

Ans: B

Explanation: The code appears to be based on a simple substitution cipher where each letter is assigned a specific number. Let’s analyze the given examples:

FILE = 8357
SINK = 9364

From this, we can deduce:
F = 8
I = 3
L = 5
E = 7
S = 9
N = ?
K = 4

We need to find the code for NIKE.

We know:
N = ?
I = 3
K = 4
E = 7

Therefore, NIKE should be: ?347

Looking back at SINK = 9364, the letter N corresponds to the number 6. So,
N = 6

Therefore, NIKE = 6347

Correct Option: B

Q. 2 If “TAPE” is coded as “SUZBOQDF” in a specific system, how would “MOCK” be coded using the same system?
Check Solution

Ans: B

Explanation: The coding system appears to involve incrementing the preceding and succeeding letters of each letter in the word.

T -> S and U (S is the preceding and U is the succeeding letter)
A -> Z and B
P -> O and Q
E -> D and F

Applying the same logic to MOCK:
M -> L and N
O -> N and P
C -> B and D
K -> J and L

Combining these, we get LNNPBDJL
Correct Option: B

Q. 3 If a specific coding system transforms “NAILS” into “PYGNU” and “TEXT” into “VCZV”, what would be the coded form of “FOREST” using the same system?
Check Solution

Ans: A

Explanation: Let’s analyze the pattern.

* N -> P (+2)
* A -> Y (-2)
* I -> G (-2)
* L -> N (+2)
* S -> U (+2)

* T -> V (+2)
* E -> C (-2)
* X -> Z (+2)
* T -> V (+2)

The pattern seems to be: +2, -2, -2, +2, +2 for NAILS and +2, -2, +2, +2 for TEXT. This pattern alternates between +2 and -2, but the -2 is not consistently in the same position. However, it seems like vowels are being shifted -2 positions and the consonants +2. Let’s see if this pattern works on FOREST.

* F -> H (+2)
* O -> M (-2) (not M in any of the choices, this indicates that the pattern is wrong)

Let’s look into a second pattern.
* N-> P (14 to 16, +2)
* A -> Y (1 to 25, -2)
* I -> G (9 to 7, -2)
* L -> N (12 to 14, +2)
* S -> U (19 to 21, +2)

* T -> V (20 to 22, +2)
* E -> C (5 to 3, -2)
* X -> Z (24 to 26, +2)
* T -> V (20 to 22, +2)

Applying to FOREST, it seems like vowels are -2 and consonants are +2.
* F (+2) -> H
* O (-2) -> M
* R (+2) -> T
* E (-2) -> C
* S (+2) -> U
* T (+2) -> V
This gives HMTCUV, but this is not the answer choices.
Considering the positions of the letters in the English alphabet, another possible pattern is +2, -2, -2, +2, +2.
So:
F (+2) = H
O (-2) = M
R (-2) = P
E (+2) = G
S (+2) = U
T (+2) = V
This would be HMPGUV, none of the answer choices.

Let’s try: +2,-2,-2,+2,+2 in pattern of “NAILS” to encode “FOREST”.
F + 2 = H
O – 2 = M
R – 2 = P
E + 2 = G
S + 2 = U
T + 2 = V
So this leads to HMPGUV. None of answer choices match.

Let’s instead try +2, -2, -2, +2, +2 from “NAILS” and then alternate the same, using +2,-2,+2,+2 from “TEXT”. Then:

F + 2 = H
O – 2 = M
R + 2 = T
E – 2 = C
S + 2 = U
T + 2 = V

Therefore, the answer should be HMTCUV, Option A. Let’s check this again for consistency.

A. HMTCUV
F -> H (+2)
O -> M (-2)
R -> T (This is inconsistent +2 from the previous word rule.)
E -> C (inconsistent from previous word +2 rule)
S -> U (+2)
T -> V (+2)

B. HQTGUV
F->H (+2)
O -> Q (inconsistent from previous word rule)
R -> T
E -> G
S -> U
T -> V

Since no correct pattern can be identified, it’s possible a pattern is missing.
I’ll go with the choice that has letters shifted by 2, despite the pattern being inconsistent.

Correct Option: A

Q. 4 If letters A-Z are assigned odd numbers (A=1, B=3, etc.), what is the numerical value of the word HONEY?
Check Solution

Ans: C

Explanation: Assign odd numbers to letters: A=1, B=3, C=5, D=7, E=9, F=11, G=13, H=15, I=17, J=19, K=21, L=23, M=25, N=27, O=29, P=31, Q=33, R=35, S=37, T=39, U=41, V=43, W=45, X=47, Y=49, Z=51. Then substitute the values for the word HONEY: H=15, O=29, N=27, E=9, Y=49. Combine these to get 152927949.
Correct Option: C

Q. 5 If the word “FIXATION” is rearranged to become “AXIFNOIT” using a specific rule, how would the word “GLYCERIN” be rearranged following the same rule?
Check Solution

Ans: A

Explanation: The rule seems to involve rearranging the letters by taking the even-positioned letters and placing them before the odd-positioned letters. Applying this to “FIXATION”: the even letters are I, A, I, and the odd are F, X, T, O, N, resulting in AXIFNOIT
Applying the same rule to “GLYCERIN”: The even-positioned letters are L, C, E, I. The odd-positioned letters are G, Y, R, N, result in CYLGNIRE.

Correct Option: A

Q. 6 If the word “PONDERS” is transformed into “ONMCDQR” based on a specific pattern, what would be the coded form of the word “MAT” using the same pattern?
Check Solution

Ans: A

Explanation: The pattern involves shifting each letter in “PONDERS” backwards in the alphabet.
* P becomes O (shifted back 1)
* O becomes N (shifted back 1)
* N becomes M (shifted back 1)
* D becomes C (shifted back 1)
* E becomes D (shifted back 1)
* R becomes Q (shifted back 1)
* S becomes R (shifted back 1)
Applying the same pattern to “MAT”:
* M becomes L (shifted back 1)
* A becomes Z (shifted back 1)
* T becomes S (shifted back 1)
Therefore, “MAT” becomes “LZS”.
Correct Option: A

Q. 7 In a certain code language, ‘FLOWER’ is coded as ‘6121523518’ and “GARDEN’ is coded as ‘713184514’. How will “BLOSSOM’ be coded in that language?
Check Solution

Ans: C

Explanation: The code represents each letter by its position in the alphabet.
F (6), L (12), O (15), W (23), E (5), R (18) = 6121523518
G (7), A (1), R (18), D (4), E (5), N (14) = 71184514

Therefore, B (2), L (12), O (15), S (19), S (19), O (15), M (13) = 2121519191513

Q. 8 In a certain code language, ‘BIRD’ is written as ‘EULG’ and ‘HOUSE’ is written as ‘KRXWB’. How will ‘CHAIR’ be written in that language?
Check Solution

Ans: D

Explanation: Let’s analyze the pattern in the given code.
BIRD -> EULG:
B + 3 = E
I + 3 = U
R + 3 = L
D + 3 = G
Each letter’s position in the alphabet is increased by 3.

HOUSE -> KRXWB:
H + 3 = K
O + 3 = R
U + 3 = X
S + 3 = W
E + 3 = B

Following this pattern for CHAIR:
C + 3 = F
H + 3 = K
A + 3 = D
I + 3 = L
R + 3 = O
So CHAIR becomes FKDLO.

Q. 9 In a certain code language, ‘FLOWER’ is coded as ‘6121523518’ and ‘GARDEN’ is coded as ‘71184514’. How will ‘BLOSSOM’ be coded in that language?
Check Solution

Ans: A

Explanation: The code appears to be the position of each letter in the alphabet.
F is the 6th letter, L is the 12th letter, O is the 15th letter, W is the 23rd letter, E is the 5th letter, R is the 18th letter.
So, for BLOSSOM:
B is the 2nd letter.
L is the 12th letter.
O is the 15th letter.
S is the 19th letter.
S is the 19th letter.
O is the 15th letter.
M is the 13th letter.
Thus, the code is 2121519191513.

Q. 10 In a certain code language, FLOWER is written as “EHNVFQ”. How will ‘SPORTS’ be written as in that language?
Check Solution

Ans: B

Explanation: The code substitutes each letter in the original word with a letter that is found by moving two letters backward for the first three letters and two letters forward for the last three letters.
F -> E (F – 2 = E), L -> H (L – 4 = H), O -> N (O- 1 = N)
W -> V (W – 1 = V), E -> F (E+1=F), R -> Q (R-1= Q)

Therefore, for SPORTS:
S -> R (S-1= R), P -> O (P-1=O), O -> Q (O+1= Q)
R -> Q (R-1= Q), T -> O (T+1=O), S -> R (S-1=R)

Therefore SPQRTS is R O Q O R Q

Therefore SPORTS becomes ROQORS.

Next Chapter: Data Interpretation

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