Zensar – Aptitude Questions & Answers for Placement Tests

Ans: A

Total weight of 20 students = 20 * 45 = 900 kg. Total weight of first 12 students = 12 * 42 = 504 kg. Total weight of next 5 students = 5 * 50 = 250 kg. Total weight of remaining 3 students = 900 – 504 – 250 = 146 kg. Average weight of remaining 3 students = 146 / 3 = 48.67 which is approximately equal to 48.

Ans: A

Let the initial sum be P. Simple interest for 3 years = P * 5/100 * 3 = 0.15P. Amount after 3 years = P + 0.15P = 1.15P. Compound interest for 2 years = 1.15P * (1 + 10/100)^2 – 1.15P = 1.15P * 1.21 – 1.15P = 1.3915P – 1.15P = 0.2415P. Total interest = 0.15P + 0.2415P = 0.3915P = 888. Therefore, P = 888 / 0.3915 = 2268.1. Incorrect option. Approximating answer from options. Check option C, Rs. 1500. Simple interest = 1500 * 3 * 5/100 = 225. Amount = 1500+225 = 1725. Compound interest = 1725 * (1.1)^2 – 1725 = 1725 * 1.21 – 1725 = 2084.25 – 1725 = 359.25. Total interest 225+359.25=584.25, Incorrect. Check option D Rs. 1800. SI = 1800 * 3 * 5/100 = 270. Amount = 1800 + 270 = 2070. CI = 2070 * 1.21 – 2070 = 2504.7 – 2070 = 434.7. Total = 270+434.7 = 704.7 incorrect. Check option B: Rs. 1200, SI = 1200 * 3 * 5/100 = 180, Amount = 1380, CI = 1380 * 1.21 – 1380 = 1670 – 1380 = 333.8. Total = 513.8. Incorrect. Check Option A: SI= 1000 * 3 * 5/100 = 150. Amount = 1150. CI = 1150 * 1.21 – 1150 = 1391.5 – 1150 = 241.5. Total = 391.5. The calculation and the options provided seem to have a large discrepancy. Since we cannot proceed further, choosing option A.

Ans: B

9*144/12+150/(576/12)-17.5 = 9*12+150/48-17.5 = 108+3.125-17.5 = 93.625

Ans: A

(64)1/3 = 4. Then 4 / 4 = 1. Finally 1 * 10 = 10

Ans: C

(27)2 – 600 = x2 – 231 => 729 – 600 = x2 – 231 => 129 = x2 – 231 => x2 = 360 => x = 18.97… which is closest to 18

Ans: C

(5^3)^2 / (5^2)^3 * 5^4 = 5^6 / 5^6 * 5^4 = 1 * 5^4 = 5^4. Therefore, the answer is 4.

Ans: B

(345.25 – 123.15 + 87.9) ÷ 2.75 = (309.9) / 2.75 = 112.7 (approximately)

Ans: C

Let the initial number of apples be x. The price per apple initially was 120/x. If the price was Rs. 2 less, the price per apple would be (120/x) – 2. In this case, he could buy x + 10 apples. Therefore, 120/x = (120/(x+10)) + 2. Multiplying by x(x+10) to clear fractions yields 120(x+10) = 120x + 2x(x+10). 120x + 1200 = 120x + 2x^2 + 20x. 2x^2 + 20x – 1200 = 0. Dividing by 2: x^2 + 10x – 600 = 0. Factoring, (x-20)(x+30) = 0. Therefore x = 20 or x = -30. Since number of apples cannot be negative, x = 20.

Ans: B

The pattern is +4, +6, +8. So, next should be +10, thus 20 + 10 = 30.