Zoho – Aptitude Questions & Answers for Placement Tests
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Q.1 If the cost price of 10 articles is equal to the selling price of 8 articles, find the profit percentage.
Check Solution
Ans: B
Let the cost price of 1 article be $x$. Then, the cost price of 10 articles = $10x$. The selling price of 8 articles = $10x$. Therefore, the selling price of 1 article = $10x/8 = 1.25x$. Profit = Selling price – Cost price = $1.25x – x = 0.25x$. Profit percentage = (Profit/Cost price) * 100 = $(0.25x/x)*100 = 25%
Q.2 A sum of money invested at simple interest triples itself in 10 years. If the interest rate is increased by 5%, in how many years would the sum become five times itself?
Check Solution
Ans: B
Let P be the principal. Tripling means the amount becomes 3P. SI = 3P – P = 2P. SI = (P * R * T) / 100. 2P = (P * R * 10) / 100. R = 20%. With the increased rate, R = 25%. Amount = 5P, SI = 4P. 4P = (P * 25 * T) / 100. T = 16 years.
Q.3 The calendar for the year 2023 will be the same as the year:
Check Solution
Ans: B
A calendar repeats every 28 years except when a century year is not a leap year. 2023 is a non-leap year. The cycle is: Non-leap year + 1 year = Normal calendar, Non-leap year + 2 years = Skip leap year calendar, Non-leap year + 3 years = Normal calendar, Non-leap year + 4 years (leap year) = Skip leap year calendar, after 6 years is a leap year. The pattern is repeated. Therefore, 2023 calendar repeats after 6 years (2029).
Q.4 A train travels a certain distance at a uniform speed. If the speed of the train is 10 kmph more, it takes 2 hours less to cover the same distance. If the speed of the train is 10 kmph less, it takes 3 hours more. The original speed of the train is:
Check Solution
Ans: D
Let the original speed be ‘x’ kmph and the distance be ‘d’ km. Then, d/x – d/(x+10) = 2 and d/(x-10) – d/x = 3. From the first equation, d = 2x(x+10)/10 = x(x+10)/5 From the second equation, d = 3x(x-10)/10 Therefore, x(x+10)/5 = 3x(x-10)/10 (x+10)/5 = 3(x-10)/10 2(x+10) = 3(x-10) 2x + 20 = 3x – 30 x = 50 kmph.
Q.5 Two cyclists are racing on a circular track. Cyclist A completes a lap in 6 minutes, and Cyclist B completes a lap in 8 minutes. If they start at the same point and time, and cycle in the same direction, how long will it take for Cyclist A to lap Cyclist B?
Check Solution
Ans: B
Relative speed in terms of laps per minute: Cyclist A completes 1/6 lap per minute and Cyclist B completes 1/8 lap per minute. The relative speed is 1/6 – 1/8 = 1/24 laps per minute. Time taken for A to lap B is 1 / (1/24) = 24 minutes.
Q.6 A train travels a certain distance at a uniform speed. If the train had been 10 km/hr faster, it would have taken 2 hours less. If the train had been 10 km/hr slower, it would have taken 3 hours more. Find the distance traveled by the train.
Check Solution
Ans: A
Let the distance be ‘d’ km and the speed be ‘s’ km/hr. Then, d/s – d/(s+10) = 2 and d/(s-10) – d/s = 3. Solving these two equations, we get d = 600 km and s = 50 km/hr.
Q.7 Odd one out – 12, 20, 28, 36, 46, 52, 60
Check Solution
Ans: C
All numbers except 46 are divisible by 4.
Q.8 A train travels a certain distance at a speed of 60 km/hr and returns with a speed of 40 km/hr. If the total time taken for the entire journey is 15 hours, find the total distance traveled in km.
Check Solution
Ans: D
Let the distance be ‘d’ km. Time taken for the onward journey = d/60 hours. Time taken for the return journey = d/40 hours. Total time = d/60 + d/40 = 15. (2d + 3d)/120 = 15. 5d = 15 * 120. d = (15 * 120)/5 = 360 km. Total distance = 2d = 2 * 360 = 720 km.
Q.9 X, Y, and Z invest in a business. X invests Rs. 6000 less than Y and Y invests Rs. 3000 less than Z. If the total investment is Rs. 48000, and the profit is divided in the ratio of their investment, Z’s share of a profit of Rs. 24000 is:
Check Solution
Ans: B
Let Z’s investment be ‘z’. Then Y invests z-3000 and X invests (z-3000)-6000 = z-9000. Total investment: z + (z-3000) + (z-9000) = 48000 => 3z – 12000 = 48000 => 3z = 60000 => z = 20000. Z’s investment is Rs. 20000. Ratio of investments: X:Y:Z = (20000-9000):(20000-3000):20000 = 11000:17000:20000 = 11:17:20. Z’s share = (20/48) * 24000 = 10000.
Q.10 The combined age of a husband and wife is 70 years. Ten years ago, the husband was four times as old as his wife. In five years, the wife’s age will be:
Check Solution
Ans: B
Let the present ages of the husband and wife be H and W respectively. H + W = 70. Ten years ago, the husband was H – 10 and the wife was W – 10. H – 10 = 4(W – 10) H – 10 = 4W – 40 H = 4W – 30 Substitute H = 4W – 30 into H + W = 70 4W – 30 + W = 70 5W = 100 W = 20 In five years, the wife’s age will be 20 + 5 = 25.
Q.11 How many times do the hour and minute hands of a clock overlap in a 24-hour period?
Check Solution
Ans: A
The hands overlap approximately every 65 minutes. In a 12-hour period, they overlap 11 times. Therefore, in a 24-hour period, they overlap 22 times.
Q.12 A sum of money becomes Rs. 4800 in 4 years and Rs. 5400 in 7 years at simple interest. The rate of interest per annum is_____
Check Solution
Ans: A
Interest for 3 years = 5400 – 4800 = 600. Therefore, Interest for 1 year = 600/3 = 200. Principal amount = 4800 – (4 * 200) = 4000. Rate = (200/4000) * 100 = 5%.
Q.13 A milkman has 20 liters of milk which contains 20% water. He mixes it with 10 liters of pure milk. What is the percentage of water in the new mixture?
Check Solution
Ans: B
Water in the original mixture = 20 * 0.20 = 4 liters. Total mixture = 20 + 10 = 30 liters. Percentage of water in new mixture = (4/30) * 100 = 13.33%
Q.14 A tap can fill a tank in 12 hours. Due to a leak, the tank fills in 18 hours. If the tank is full, how long will the leak take to empty the full tank?
Check Solution
Ans: B
Let the capacity of the tank be the LCM of 12 and 18, which is 36 units. Tap’s filling rate is 36/12 = 3 units/hour. Tap + Leak’s filling rate is 36/18 = 2 units/hour. The leak’s rate is 3 – 2 = 1 unit/hour (emptying). Time to empty the full tank is 36/1 = 36 hours.
Q.15 The sum of the ages of a father and son is 60 years. Five years ago, the father’s age was four times the age of his son. What is the present age of the son?
Check Solution
Ans: C
Let the father’s present age be F and the son’s present age be S. F + S = 60 Five years ago, the father’s age was F-5 and the son’s age was S-5. F – 5 = 4(S – 5) F – 5 = 4S – 20 F = 4S – 15 Substitute F in the first equation: 4S – 15 + S = 60 5S = 75 S = 15
Q.16 A shopkeeper purchased pens at 5 for a rupee. To make a profit of 25%, how many pens must he sell for a rupee?
Check Solution
Ans: C
Let the cost price of 1 pen be 1/5 rupees. To gain 25%, the selling price of 1 pen must be (1/5) * 1.25 = 1/4 rupees. Therefore, he must sell 4 pens for 1 rupee.
Q.17 A 200-meter-long train is traveling at 72 kmph. It passes a stationary platform. In what time will the train completely clear the platform, if the platform is 100 meters long?
Check Solution
Ans: B
Total distance to be covered = length of train + length of platform = 200 + 100 = 300 meters. Speed of train = 72 kmph = 72 * (5/10) m/s = 20 m/s. Time = distance/speed = 300/20 = 15 seconds.
Q.18 In how many ways can the letters of the word ‘ENGINEERING’ be arranged?
Check Solution
Ans: A
The word ENGINEERING has 11 letters. The letter E appears 3 times, N appears 3 times, G appears 2 times, I appears 2 times and R appears 1 time. Therefore the number of arrangements is 11! / (3! * 3! * 2! * 2! * 1!) = (11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1) / (6 * 6 * 2 * 2 * 1) = 39916800 / 144 = 277200
Q.19 A bag contains 5 red balls, 3 green balls, and 2 blue balls. If a ball is drawn at random, the probability that it is not a green ball is?
Check Solution
Ans: B
Total balls = 5 + 3 + 2 = 10. Balls that are not green = 5 (red) + 2 (blue) = 7. Probability = 7/10
Q.20 A boat travels 36 km downstream and 24 km upstream in a total of 6 hours. The speed of the boat in still water is 10 km/hr. Find the speed of the stream.
Check Solution
Ans: A
Let the speed of the stream be x km/hr. Downstream speed = (10 + x) km/hr, Upstream speed = (10 – x) km/hr. Time downstream = 36 / (10 + x) hours. Time upstream = 24 / (10 – x) hours. Total time = 6 hours. 36 / (10 + x) + 24 / (10 – x) = 6 36(10 – x) + 24(10 + x) = 6(10 + x)(10 – x) 360 – 36x + 240 + 24x = 6(100 – x^2) 600 – 12x = 600 – 6x^2 6x^2 – 12x = 0 6x(x – 2) = 0 x = 0 or x = 2. Since speed of the stream cannot be 0, x = 2.
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