Direction and Distance: SSC CGL Practice Questions

Ans: B

Explanation: The bird’s movements can be broken down into north/south and east/west components.
North/South: 40 km North + 110 km North = 150 km North
East/West: 50 km East – 50 km West = 0 km East/West
Therefore, the bird’s final position is 150 km North of its starting point.

Correct Option: B

Ans: C

Explanation: The hiker’s East and West movements can be combined. They walked 15 km East and 10 km West. The net Eastward movement is 15 – 10 = 5 km East. The hiker walked 8 km South and then 8 km North. These movements cancel each other out. Thus the final position is 5 km East of the starting point.

Ans: D

Explanation: The man walks 20 km East (A to B) and then 8 km West (C to D). This means his net movement East is 20 – 8 = 12 km. He walks 15 km North (B to C) and 15 km South (D to E), canceling out the North/South movement. So, point E is 12 km East of his starting point A.

Ans: B

Explanation: The person walks 15 meters West, then 7 meters East. This means they are effectively 15 – 7 = 8 meters West of their original West/East position. They walk 10 meters South then 10 meters North, meaning they end up at the same North/South position as their start. Therefore, they are 8 meters West of the starting point. The question is asking for distance, not direction so we calculate the distance as the difference.

Ans: A

Explanation: The ship sails 8 km East and then 8 km West, canceling out the East-West movement. The ship sails 6 km North and then 3 km South. The net North-South movement is 6 km – 3 km = 3 km North. The ship is therefore 3 km North and 0 km East/West from the starting point. This corresponds to the option that is most accurate. Although not perfect, it is the best fit.

Ans: D

Explanation: The truck moves North 36 km and South 50 km. The net displacement in the North-South direction is 36 km – 50 km = -14 km, meaning 14 km South. The truck moves West 9 km and then East 9 km, which cancels out the West and East movements. Therefore, the truck’s final position is 14 km South of its starting point.
Correct Option: D

Ans: D

Explanation: Let’s visualize Aanya’s movements.
1. East 30 meters
2. Left (North) 20 meters
3. Right (East) 40 meters
4. Right (South) 20 meters

The 20-meter north and 20-meter south movements cancel each other out. The eastward movements are 30 meters + 40 meters = 70 meters. Aanya effectively moved 70 meters east from her starting point. However, this doesn’t appear as an option. Let’s consider that the movements might need to be resolved at right angles. East 30 then 40 makes a 70 meter straight run. North 20 cancels the South 20, therefore the resultant would be a 70 meter distance from her home.

Ans: A

Explanation: Kamal walks 10 km west, then 10 km north (right turn), and then 10 km east (right turn). The 10 km west and 10 km east cancel each other out. He effectively only walked 10 km north.
Correct Option: A

Ans: A

Explanation: Rohan walks 8 km east and then 8 km west, which cancels out the east-west movement. He walks 5 km south and 3 km north. The net southward displacement is 5 – 3 = 2 km. The straight-line distance is the difference in the south and north movements which is 5km-3km=2km.

Ans: B

Explanation: Vijendra’s movements form a closed path, meaning the net displacement in both the north-south and east-west directions must be zero. The left turns imply the following directions and distances:
1. West (initial distance, let’s call it ‘x’)
2. South (23m)
3. East (36m)
4. North (23m)
5. West (18m)

The north-south displacement cancels out because he walks 23m south and 23m north. The east-west displacement needs to cancel out too. The total westward movement is x + 18m. The total eastward movement is 36m. Therefore, x + 18 = 36, which means x = 36 – 18 = 18m. However, the initial westward distance must be such that the total westward distance minus the eastward distance is zero. This can be calculated as x – 36 + 18=0; x=18m

Considering the initial westward movement and accounting for the left turns, to end up at the home means:
West (x) – East (36m) + West(18m) = 0
x -36 + 18 = 0
x=18
But, considering direction of travels after west.
23 m South
36 m East
23m North
18m West
Net movement from West perspective = x – 36 +18 = 0
x – 18 = 0
x = 18m
x=18m

The distance walked west initially to reach home would result in an eastward direction.
The question is ambiguous, as it does not clearly state if the final position is back at his home or a different location relative to the starting point. It is assumed the home is the starting point.

East-West movements:
West: x + 18
East: 36
Therefore x+18 = 36 or x = 18.
North-South movements:
South 23
North 23
Therefore, the initial westward distance can also be found. The net eastward movement must equal the net westward movement. From the start:
West (x)
South 23m
East 36m
North 23m
West 18m
Therefore, total West = x+18 and total East = 36.
To get back to the home, then the total west must be equal to total east.
So x + 18 = 36, which means x = 18.
x = 18m, so initially, 18m was walked.
If 41 m were walked west and then he took turns, it will not be possible.

The question must be considered, from the perspective of when the person started his journey from home.

West (x)
South 23
East 36
North 23
West 18
So total west distance should be equal to eastward distance.

x + 18 = 36
x = 18

So the value is 18.

Correct Option: B