Statistics – SSC CGL Mock Test 10 Qs | 10 Marks | 5 MinsNo negative markingPlease input correct details for the leaderboard Name Email City 1. If the equation of the exponential trend with 2004 as origin is $Y = 20(1.5)^x$, then the equation of the exponential trend with 2006 as origin is: Y = 20 / (1.5)x Y = 45(1.5)x Y = 8.89(1.5)x Y = 20(1.5)x None 2. If $Z \sim \Phi(0, 1)$ is a standard normal variate, then $Z^2$ follows: chi-squared distribution with degree of freedom 1 standard normal distribution with μ = 0 and σ = 1 log-normal distribution with μ = 0 and σ = 1 bi-standard normal distribution with μ = 0 and σ = 1 None 3. Suppose a person would earn Rs. 10,000 in base period. Suppose the cost of living index increases by 20% over base period. Then the employers of that person increase his salary by Rs. 1500. Which of the following option is TRUE? He is just able to maintain the same standard of living as in base period. He should claim Rs. 500/- as Dearness Allowance. He can improve his standard of living as compared to base period. He should claim Rs. 2,000 as Dearness Allowance. None 4. The given histogram represents the marks of students in Mathematics test of a certain class. The total number of students is 350. Study the graph and answer the question that follows. What is the ratio of the total number of students who scored 140 marks and above to the total number of students who scored marks between 60 to 120? 137 : 110 110 : 137 9 : 11 11 : 9 None 5. The data relating to the donation, in hundreds, for welfare in the village of 543 members is follows. Amount 20 30 40 50 60 70 80 No. of members: 3 61 132 153 140 51 3 The decile D 6 for this data is: 55 45 50 40 None 6. A random sample of size 81 is taken from a normal population with unknown mean μ and known standard deviation σ = 0.90. If the sample mean is x̅ = 20 and the upper 2.5% point of a standard normal variable is T 0.025 = 1.96, then 95% confidence interval for μ is: (18.90, 21.40) (18.60, 21.80) (18.40, 21.60) (19.80, 20.20) None 7. In one-way ANOVA, $\sigma^2$ is estimated by: mean square between groups sum of squares between groups mean square within groups S2 None 8. Based on results of 2 way ANOVA, the SSE was computed to be 139.4. If we ignore one of the factors and perform one way ANOVA using the same data, SSE will: remain same increase Either (1) or (2) decrease None 9. In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6 The MSE for the analysis would be: 44.4 14.8 39.9 133.2 None 10. Calculate the coefficient of range for the following series: Item 10 12 14 16 18 20 22 Frequency 5 3 8 12 34 63 8 0.17 0.47 0.37 0.27 None 1 out of 10 Practice SSC CGL Topic wise Mock TestsCrack SSC CGL with Adaptive PracticeAdaptive Practice | Real Time ProgressStart Practice!
