Placement Aptitude Test | Check Your Rank | Free Practice!

This mock test is designed to mimic placement aptitude tests for engineering students. Attempt the test, check your ranking, and invite your friends to join as well.

Section 1: Quant

Section 1: Quantitative Aptitude (Placement Mock Test)

  • 10 Qs | 10 Marks | 10 Mins
  • No negative marking
  • Please input correct details for the leaderboard

Section 2: Reasoning

Section 2: Logical Reasoning (Placement Mock Test)

  • 10 Qs | 10 Marks | 10 Mins
  • No negative marking
  • Please input correct details for the leaderboard

Section 3: Verbal

Section 3: Verbal Ability (Placement Mock Test)

  • 10 Qs | 10 Marks | 5 Mins
  • No negative marking
  • Please input correct details for the leaderboard

Leaderboard

RankNameCollegeQuantReasoningVerbalFinal Score
๐Ÿฅ‡abcabc1071027
๐ŸฅˆMSNM1071027
๐Ÿฅ‰Rajasi PPTVA's Institute of Management1071027
4VidishIIT Roorkee1061026
5Satyajeet KumarNIT Rourkela1051025
6Ayush RajIIT K96924
7KanishkJSSATE106824
8AdityaIIT BHU96924
9S kiit d107724
10JashIIT BHU105823
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Solutions

Please note that order might be different as questiosn ae randomized in the test

Quant Solutions

Sol : 1

Original Price = 200

Price after a 20% increase = 200+(20% of 200)=200+40=240

Price after a 10% discount on 240 = 240โˆ’(10% of 240)=240โˆ’24=216

Sol : 2

A=$5000 * (1+8/100โ€‹)^2 = 5000*(1.08)^2$

= 5000ร—1.1664 = 5832$

Sol : 3

Based on given ration, let number of boys, girls and teachers be 33x, 53x and 2x.

Given, 2x=10, so x=5

Number of students = (33x + 53x)=86ร—5=430

Sol : 4

Loss = CP – SP = 5400 – 4500 = 900

Loss % = 900/ 5400*100 = 16.67%

Sol: 5

Subtracting the two equations:

$x+y – (xโˆ’y)=12 – 4$

$2y = 8$

$y = 4$

Sol : 6

Let the five consecutive numbers be xโˆ’2, xโˆ’1, x, x+1 and x+2

Their average = x=15

Smallest number = xโˆ’2=13; and largest = x+2=17

Sum of smallest and largest = 13+17 = 30

Sol: 7

Convert the speed into km/hr first

Speed = 30m/s = 30*3600/1000 = 108 km/hr

Time = 240/108 = 2.22 hour

Sol : 8

Total work = 6 menร—8 days=48 man-days

For 4 men, days required = 48 /4 =12

Sol : 9

Use direct formula of area of circle = $\pi*r^2$

Sol: 10

Number of arrangements = 4!

Reasoning Solutions

Sol : 1

Z (26), Y (25), W (23), T (20), P (16)

The pattern is: -1, -2, -3, -4

Following the pattern, the next term will be Pโˆ’5=M

Sol : 2

Every letter is increased by 1

Sol : 3

The man is the son of Sarahโ€™s mother or father, which makes him Sarah’s brother.

Sol : 4

The problem states a clear requirement of 5 years of experience. Although Jane has the required qualification, she lacks the experience, so based on the strict criteria, she should not be selected.

Sol : 5

The statement implies that planning aids in success, but it doesnโ€™t imply exclusivity. Hence, assumption B is correct.

Sol : 6

U is second from the right, so position 5 is U.Since Q is between P and R, and S is to the left of T, the order is:

P – Q – R and S – T – U

With U in the fifth position, R must be on the right end (position 6).

Sol : 7

2024 is a leap year, so it has 366 days.

From February 15, 2024, to February 15, 2025, there are 366 days.

366 days = 52 weeks + 2 extra day. Thus, the day will shift by 2 days

Sol : 8

Starting at south, turns go as follows:

  1. Right to west
  2. Left to south
  3. Left to east

So, Sarah is facing east.

Sol : 9

Dots are moving by 90 degree in each step

Sol : 10

Assume B has x apples, A will have x + 4 and C will have 2x.

Solve to get x = 6

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If you are someone starting your aptitude preparation from scratch, we highly recommend going through a preparation structure we have built for you: https://www.learntheta.com/placement-aptitude-preparation/

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