Zeros (Roots) of a Polynomial: Concept & Calculation

The zeros (also called roots) of a polynomial are the values of the variable (usually *x*) that make the polynomial equal to zero. In simpler terms, they are the *x*-values where the graph of the polynomial crosses the x-axis (the x-intercepts).

Understanding zeros is crucial for solving polynomial equations, sketching the graph of a polynomial, and analyzing its behavior.

Formulae

The general form of a polynomial is:

$P(x) = a_nx^n + a_{n-1}x^{n-1} + … + a_1x + a_0$

Where:

  • $P(x)$ represents the polynomial.
  • $x$ is the variable.
  • $a_n, a_{n-1}, …, a_1, a_0$ are the coefficients (real numbers).
  • $n$ is the degree of the polynomial (a non-negative integer).

To find the zeros, we set $P(x) = 0$ and solve for $x$.

Examples

Example-1: Finding the Zeros of a Quadratic Polynomial

Find the zeros of the polynomial $P(x) = x^2 – 5x + 6$.

Solution:

  1. Set $P(x) = 0$: $x^2 – 5x + 6 = 0$
  2. Factor the quadratic equation: $(x – 2)(x – 3) = 0$
  3. Solve for *x*:
    • $x – 2 = 0 \Rightarrow x = 2$
    • $x – 3 = 0 \Rightarrow x = 3$
  4. Therefore, the zeros of the polynomial are $x = 2$ and $x = 3$.

Example-2: Finding the Zeros of a Cubic Polynomial

Find the zeros of the polynomial $P(x) = x^3 – 4x^2 + x + 6$.

Solution:

  1. Set $P(x) = 0$: $x^3 – 4x^2 + x + 6 = 0$
  2. By rational root theorem or by observation, we can see that $x=-1$ is a zero. So $(x+1)$ is a factor. We do polynomial division by $(x+1)$ to factorize the polynomial.
  3. Divide $x^3 – 4x^2 + x + 6$ by $(x+1)$ to get the quadratic factor $x^2-5x+6$.
  4. Now the polynomial can be expressed as: $(x+1)(x^2-5x+6) = 0$.
  5. Factor the quadratic equation: $(x – 2)(x – 3) = 0$
  6. Solve for *x*:
    • $x + 1 = 0 \Rightarrow x = -1$
    • $x – 2 = 0 \Rightarrow x = 2$
    • $x – 3 = 0 \Rightarrow x = 3$
  7. Therefore, the zeros of the polynomial are $x = -1$, $x = 2$ and $x = 3$.

Theorem with Proof

The Factor Theorem: A polynomial $P(x)$ has a factor $(x – c)$ if and only if $P(c) = 0$.

Proof:

If part: Assume $(x – c)$ is a factor of $P(x)$. Then we can write $P(x) = (x – c)Q(x)$ for some polynomial $Q(x)$. Substituting $x = c$, we get $P(c) = (c – c)Q(c) = 0 \cdot Q(c) = 0$.

Only if part: Assume $P(c) = 0$. By the Remainder Theorem, when we divide $P(x)$ by $(x – c)$, the remainder is $P(c)$. Since $P(c) = 0$, the remainder is 0. Therefore, $(x – c)$ is a factor of $P(x)$.

Common mistakes by students

  • Incorrect Factoring: Students often struggle with factoring polynomials, especially higher-degree ones. This leads to incorrect zeros. Practice factoring techniques (e.g., grouping, using the rational root theorem) is crucial.
  • Forgetting Multiple Zeros: A zero can occur multiple times (e.g., $(x-2)^2$ has a zero of 2 with a multiplicity of 2). Students sometimes miss these repeated roots.
  • Confusing Zeros and Coefficients: Students might confuse the zeros (solutions for x) with the coefficients of the polynomial.
  • Incorrect Use of the Quadratic Formula: Students make mistakes when applying the quadratic formula ($x = \frac{-b \pm \sqrt{b^2 – 4ac}}{2a}$) to solve quadratic equations, such as incorrect substitutions or calculation errors.

Real Life Application

Polynomials and their zeros have various real-world applications:

  • Engineering: Used in designing bridges, buildings, and other structures. Zeros help determine points of stability and stress.
  • Physics: Used to model projectile motion, wave behavior, and the motion of objects. Zeros can represent points of impact or equilibrium.
  • Economics: Used to model cost, revenue, and profit functions. Zeros can indicate break-even points or the point where profit is zero.
  • Computer Graphics: Used in creating curves and surfaces.

Fun Fact

The Fundamental Theorem of Algebra states that a polynomial of degree *n* has exactly *n* complex roots (zeros), counting multiplicity. This means a quadratic equation (degree 2) has two roots, a cubic equation (degree 3) has three roots, and so on. Some of these roots may be real and some may be complex numbers.

Recommended YouTube Videos for Deeper Understanding

Q.1 What is the sum of the zeros of the quadratic polynomial $x^2 – 5x + 6$?
Check Solution

Ans: C

The sum of the zeros of a quadratic $ax^2 + bx + c$ is given by $-b/a$. Here, a=1 and b=-5, so the sum is $-(-5)/1 = 5$.

Q.2 Which of the following is a zero of the polynomial $p(x) = x^3 – 8$?
Check Solution

Ans: C

A zero of a polynomial is a value of x for which p(x) = 0. Substituting x=2 into p(x), we get $2^3 – 8 = 8 – 8 = 0$.

Q.3 If 3 is a zero of the polynomial $f(x) = x^2 – kx – 15$, then the value of k is:
Check Solution

Ans: A

If 3 is a zero, then f(3) = 0. Substituting x=3 into f(x), we get $3^2 – 3k – 15 = 0$, or $9 – 3k – 15 = 0$. Simplifying gives $-3k – 6 = 0$, so $-3k = 6$ and $k = -2$.

Q.4 How many real zeros does the polynomial $f(x) = x^2 + 4$ have?
Check Solution

Ans: A

Setting $x^2 + 4 = 0$, we get $x^2 = -4$. Since the square of a real number cannot be negative, there are no real zeros.

Q.5 The zeros of the polynomial $g(x) = x^2 – 4x$ are:
Check Solution

Ans: A

To find the zeros, set $x^2 – 4x = 0$. Factoring, we get $x(x – 4) = 0$. This implies that $x = 0$ or $x – 4 = 0$, so $x = 4$.

Next Topic: Remainder Theorem: Statement & Applications

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