Caselet based Data Interpretation Questions
Caselet based Data Interpretation is one of the common formats across CAT, GMAT and Banking Exams. In these questions instead of charts or tables, numbers and details are wrapped in a detailed caselet. Exam is testing your skill to extract useful information, structure it in logical fashion and finally do the calculations to arrive at the required number.
Caselet 1
The Central Bank recently implemented new reserve requirements for commercial banks. These requirements are designed to control inflation and ensure financial stability. Bank A, a large national bank, has a total deposit base of 500 billion rupees. The Reserve Requirement (RR) mandates that banks hold a certain percentage of their deposits in reserves.
The RR varies based on the type of deposit. For demand deposits (checking accounts), the RR is 10%. Time deposits (savings accounts and fixed deposits) require a 5% RR. Bank A has a 60:40 ratio of demand deposits to time deposits.
The Central Bank also imposes a Statutory Liquidity Ratio (SLR), which requires banks to invest a percentage of their total deposits in government securities. The SLR is set at 18% for all banks. Bank A also had outstanding loans of 350 billion rupees. The bank’s non-performing assets (NPAs) currently stand at 3% of the loan amount. The average interest rate on Bank A’s deposits is 6.5%. The average interest rate on Bank A’s loans is 10%.
Further, the bank holds some of its reserves in the form of balances maintained with the central bank. These balances constitute 60% of Bank A’s total reserves.
Question: Based on the information provided, what is the value of the non-performing assets (in billion rupees) of Bank A?
A. 5.25
B. 10.5
C. 15
D. 21
Solution
Answer:10.5
Calculate the value of Non-Performing Assets (NPAs):
- NPA percentage = 3%
- Loan amount = 350 billion rupees
- NPAs = 3% of 350 billion = (3/100) * 350 billion = 10.5 billion rupees
Caselet 2
A language proficiency assessment was conducted across four different schools – A, B, C, and D – focusing on spelling accuracy. The assessment involved 150 students from each school, each taking a spelling test. The test was graded out of 100 points.
In School A, 60% of the students scored above 75, with an average score of 82 for this group. The remaining students in School A scored an average of 68.
School B had a slightly lower overall performance. The ratio of students scoring above 75 to those scoring below or equal to 75 was 1:2. The average score of students who scored above 75 was 85, while the average score for the other group was 65.
School C showed a more even distribution. 40% of the students scored above 75, with an average score of 88. The students who scored above 75 had an average score of 88. The students who scored below or equal to 75 scored an average of 60.
In School D, the average score of all 150 students was 72. The percentage of students who scored above 75 was 50%, with the students who scored above 75 getting an average score of 80. The average score for the remaining students was not provided.
Question: Based on the information provided, what is the absolute difference between the average score of all students in School A and the average score of all students in School D?
A. 8.8
B. 2.2
C. 3.3
D. 4.4
Solution
School A:
- Students scoring above 75: 60% of 150 = 90 students
- Average score above 75: 82
- Students scoring <= 75: 150 – 90 = 60 students
- Average score <= 75: 68
- Total score in School A: (90 * 82) + (60 * 68) = 7380 + 4080 = 11460
- Average score in School A: 11460 / 150 = 76.4
School D:
- Students scoring above 75: 50% of 150 = 75 students
- Average score above 75: 80
- Average score of all students in D: 72
- Let ‘x’ be the average score of students scoring <= 75.
- Total score in D: (75 * 80) + (75 * x) = 6000 + 75x
- Average score in School D: (6000 + 75x) / 150 = 72
- 6000 + 75x = 10800
- 75x = 4800
- x = 64
- Total score in D = 7580 + 7564 = 6000 + 4800 = 10800
- Average score in D = 10800/150 = 72
Absolute Difference: |76.4 – 72| = 4.4
Answer:4.4