Patterns: Bank Exam Practice Questions (SBI, IBPS, RRB, PO & Clerk)
Q. 1 A nine-digit number, 256463127, undergoes a transformation where even digits are reduced by 2 and odd digits are increased by 2. After this transformation, what is the product of the digit in the fifth position from the left and the digit in the second position from the right?
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Ans: A
Explanation: The original number is 256463127. Let’s apply the transformation:
– 2 (even) becomes 2 – 2 = 0
– 5 (odd) becomes 5 + 2 = 7
– 6 (even) becomes 6 – 2 = 4
– 4 (even) becomes 4 – 2 = 2
– 6 (even) becomes 6 – 2 = 4
– 3 (odd) becomes 3 + 2 = 5
– 1 (odd) becomes 1 + 2 = 3
– 2 (even) becomes 2 – 2 = 0
– 7 (odd) becomes 7 + 2 = 9
The transformed number is 074245309. The digit in the fifth position from the left is 4. The digit in the second position from the right is 0. The product of these two digits is 4 * 0 = 0.
Correct Option: A
Q. 2 How many digits in the number 84279613 remain in the same position if the digits are arranged in descending order?
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Ans: E
Explanation: First, arrange the digits of the number 84279613 in descending order: 98764321. Now, compare this sorted number with the original number 84279613. The digit 8 is in the second position in both. The digit 4 appears in the sixth place in the sorted and second in original. The digit 2 appear in the eighth place in the sorted and the third in original. The digit 7 is third and seventh in the sorted and original respectively. The digit 9 is first and fifth in the sorted and original respectively. The digit 6 is fourth and sixth in the sorted and original respectively. The digit 1 is ninth and seventh in the sorted and original respectively. The digit 3 is fifth and eighth in the sorted and original respectively. The only digit in same positions is 8 and 1.
Q. 3 If it is possible to make a meaningful word from the 2nd and 4th letters of the word ‘GLAD’ and the 1st and 3rd letters of the word ‘TEAM’, then which will be the third letter from the left? If more than one word can be formed, mark it as ‘X’; otherwise, mark it as ‘Y’.
Check Solution
Ans: C
Explanation: The 2nd and 4th letters of ‘GLAD’ are L and D. The 1st and 3rd letters of ‘TEAM’ are T and A. Combining these letters, we can form the word “LAD” and “TAD” and “DAL”. Since more than one meaningful word can be formed, the answer is ‘X’.
Q. 4 If the letters in the word JUNIOR are rearranged in alphabetical order, how many letters will stay in the same position?
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Ans: A
Explanation: First, arrange the letters of JUNIOR in alphabetical order: I J N O R U. Now, compare this with the original word JUNIOR:
– J (original) vs. I (arranged) – Different position
– U (original) vs. J (arranged) – Different position
– N (original) vs. N (arranged) – Same position
– I (original) vs. O (arranged) – Different position
– O (original) vs. R (arranged) – Different position
– R (original) vs. U (arranged) – Different position
Only the letter ‘N’ stays in the same position.
Correct Option: A
Q. 5 If you arrange the words MNO, ABD, ATE, POT, and KLO in alphabetical order (like a dictionary), which word would be the third word if you read the list from right to left?
Check Solution
Ans: D
Explanation: First, arrange the words in alphabetical order: ABD, ATE, KLO, MNO, POT. Now, read the list from right to left: POT, MNO, KLO, ATE, ABD. The third word in this reversed list is KLO.
Correct Option: D
Q. 6 In the number 7298641350, subtract two from each odd digit and add one to each even digit. What is the sum of the third digit from the left and the fifth digit from the right in the resulting number?
Check Solution
Ans: D
Explanation: Let’s apply the given operations to the number 7298641350.
– 7 becomes 7 – 2 = 5
– 2 becomes 2 + 1 = 3
– 9 becomes 9 – 2 = 7
– 8 becomes 8 + 1 = 9
– 6 becomes 6 + 1 = 7
– 4 becomes 4 + 1 = 5
– 1 becomes 1 – 2 = -1 (This is the tricky part! We can’t have a negative digit in a standard number representation. However, the question doesn’t specify any restrictions on the resulting digits, so we continue with this calculation).
– 3 becomes 3 – 2 = 1
– 5 becomes 5 – 2 = 3
– 0 becomes 0 + 1 = 1
The resulting number is 537975(-1)131. The original question has specified to take the 3rd number from the left and the 5th number from the right. The third digit from the left is 7. The fifth digit from the right is 5.
7 + 5 = 12.
Next Chapter: Percentages
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