Tavant Technologies – Aptitude Questions & Answers for Placement Tests

Ans: D

First, find Y using SI = PRT/100. 450 = 1500 * 10 * Y / 100. Y = 3. Then find the principal for CI = 3 + 2000 = 2003. Using CI formula, CI = P(1+R/100)^T – P. CI = 2003(1+10/100)^2 – 2003 = 2003(1.21) – 2003 = 2423.63 – 2003 = 420.63.

Ans: B

Let A, B, and C represent the ages of Alice, Bob, and Carol, respectively. We are given: 1. A = (1/2)C + 3 2. Bob is the youngest, and 4 years older than the other sibling, so he is 2 years younger than one and 4 years older than the other. B=C-2 and B=A-4, and since Bob is the youngest sibling. 3. From (2) we know B=A-4, so A=B+4. 4. Substituting A=B+4 into (1): B+4 = (1/2)C + 3, which gives B = (1/2)C – 1 5. Also from 2 B=C-2; (1/2)C -1 = C-2, so C=2. Then B=2-2=0, which means Carol is two years old and bob zero. Not possible, so Bob can’t be C-2, or C= B+2. Bob must be, B=A-4 and A = C-2. Bob is also the youngest. 6. Then A=C-2, and also A=(1/2)C+3 so C-2=(1/2)C+3, so (1/2)C=5, or C=10, and A=8. B=C-2=8, but also from B=A-4. Since A=8 and B=4 so B should be 4 not 8. 7. Then B=A-4 and B=C-2 , as Bob is the youngest. So A = C-2+4 = C+2. 8. A=(1/2)C+3, and A=C+2, so (1/2)C+3=C+2, (1/2)C=1, or C=2. 9. If C=2, A=C+2 =4 and B=C-2 = 0. This is not possible because A=(1/2)C+3 = 1+3 =4. B=0, A=4, C=2. then A+B+C = 4+0+2=6. Incorrect If A=C-2, then C-2=(1/2)C+3 then (1/2)C=5 and C=10 and so A=8, Bob is 4, and Carol is 10, making Bob the youngest. 4+8+10=22. But now Alice is only 4 years older not 4. Bob can be 4 years younger than Carol, A = C-4, and B =C-2. A=(1/2)C+3 and A=C-2. So C-2=(1/2)C+3, or C=10, so A=8, and B=6. C=10, B=6. A=8. 8+6+10=24

Ans: C

Let the hundreds digit be ‘h’, the tens digit be ‘t’, and the units digit be ‘u’. We have: 1) h + t + u = 12 2) h = 2t 3) 100u + 10t + h = 100h + 10t + u – 396 => 99h – 99u = 396 => h – u = 4 Substitute h = 2t into equation 1: 2t + t + u = 12 => 3t + u = 12 Substitute h = 2t into equation 3: 2t – u = 4 Adding the equations 3t + u = 12 and 2t – u = 4 gives 5t = 16, which does not give an integer. Trying different approaches for solution, we can substitute options: Option A (426): 4+2+6=12; 4=2*2 ; 624-426 is not 396 Option B (840): 8+4+0=12; 8=2*4; 048 – 840 = -792 Option C (624): 6+2+4=12; 6=2*3; 426-624 = -198 Option D (930): Incorrect sum of digits and other wrong answers. Checking each option, the correct form: h = 2t and h-u = 4. If h = 6, t = 3, then u = 2. The sum is 11. Reverse it 236. Then: 632 – 236 = 396. Recheck the question – a bit tricky. If we consider reverse to be less. Then h-u=4. h=2t, h+t+u=12 h=6, t=2, u=4; 624-426=198; If we make this assumption h>u, and find an answer that complies. Lets start the second attempt. h=2t 1. h+t+u=12. 2. Reverse gives 100u+10t+h which is less than original. 3. 100h+10t+u – (100u+10t+h)=396 99h-99u=396 h-u=4 From (1), using h=2t gives 2t+t+u=12 or 3t+u=12. h=2t means 2t-u=4 or 3t+u=12 Adding 2t-u=4 to 3t+u=12, results 5t=16. Let h=8, t=4, u=0. (8+4+0 is not 12). From our calculation h-u=4, we assume 624, 6=2(3), and sum is 12. And 6-4 is incorrect Let t=2. then h=4. 42x 42x and reversed is x24. 426-624 = -198. h=6; t=3, u=3. 336 Using h-u=4 From the question : the new number is 396 less. Reversing gives less so: 100h+10t+u-(100u+10t+h)=396, so h-u=4 h=2t h+t+u=12. Try C. 624 6+2+4=12. 6/2=3. 426. 624-426 = 198. h-u=4. 6-4=2. Using the clues h=6. 624: h-u=4. 6-u=4. h+t+u=12. 6+2+u=12 =>u=4. Checking option C: 624 Reverse is 426 6+2+4=12 6 = 2 * 3 (incorrect) So reverse = 426, 6-4 not 4 h-u=4 We expect the original number to be greater. Trying: 840 048-840=396 is not true. -792. Try 633; 6/3=2 NOT.

Ans: A

Perimeter of square = 4 * 12 = 48 cm. Since the perimeters are equal, perimeter of triangle = 48 cm. Side of equilateral triangle = 48/3 = 16 cm. Area of equilateral triangle = (√3/4) * side^2 = (√3/4) * 16^2 = 64√3 cm^2. The closest value is not within the options, so there may be a calculation error in the prompt or in the options.

Ans: B

Let ‘x’ be the original number of workers. The total work can be represented as the number of workers multiplied by the number of days. So, 15x = 18(x – 8). Expanding the equation: 15x = 18x – 144. Rearranging terms: 3x = 144. Therefore, x = 48.

Ans: B

Treat all the E’s as a single unit (EEEE). Now we have the following units to arrange: (EEEE), G, N, N, R, I, I. There are a total of 7 units. Number of arrangements = 7! / (2! * 2!) = 5040/4 = 1260.

Ans: A

Treat the five E’s as a single unit (EEEEE). Now we arrange the remaining letters: G, N, N, R, I, I, and the (EEEEE) unit. There are 8 “objects” to arrange, with 2 N’s and 2 I’s. The number of arrangements is 8! / (2! * 2!) = 40320 / 4 = 10080. So it should be calculated as 8!/(2!2!) .

Ans: B

Let the number be x. Then, 0.4x – 0.2x = 21 => 0.2x = 21 => x = 21/0.2 = 105

Ans: A

First, find the rate of one typist: 10 pages / 5 minutes = 2 pages/minute. Then, calculate the combined rate of 8 typists: 8 typists * 2 pages/minute/typist = 16 pages/minute. Finally, calculate the total pages typed in 20 minutes: 16 pages/minute * 20 minutes = 320 pages.