Syntel – Aptitude Questions & Answers for Placement Tests

Reviewing Previous Year Questions is a good start. Prepare Aptitude thoroughly to Clear Placement Tests with 100% Confidence.

Q.1 683-213=?
Check Solution

Ans: A

683-213=470

Q.2 48 / 4 + 15 – 2 * 6 = ?
Check Solution

Ans: C

48 / 4 = 12; 2 * 6 = 12; 12 + 15 – 12 = 15

Q.3 72 * 8 * 15 / ? = 72
Check Solution

Ans: B

(72 * 8 * 15) / ? = 72 => ? = (72 * 8 * 15) / 72 = 8 * 15 = 120 / 72 = 120

Q.4 9[2/5] – 3[1/2] + 1[3/10] = ?
Check Solution

Ans: A

9[2/5] – 3[1/2] + 1[3/10] = (9 + 2/5) – (3 + 1/2) + (1 + 3/10) = 9 + 2/5 – 3 – 1/2 + 1 + 3/10 = (9 – 3 + 1) + (4/10 – 5/10 + 3/10) = 7 + 2/10 = 7 + 1/5 = 7[1/5]

Q.5 The volume of a cube is 2744 cubic centimeters. What is the surface area of the cube?
Check Solution

Ans: B

The volume of a cube is given by side^3, so side = cube root of volume = cube root of 2744 = 14 cm. The surface area of a cube is given by 6 * side^2 = 6 * 14^2 = 6 * 196 = 1176 square centimeters.

Q.6 What will be the compound interest on a sum of Rs. 10000/- at 10 p.c.p.a. for 3 years?
Check Solution

Ans: A

CI = P(1 + R/100)^N – P = 10000(1 + 10/100)^3 – 10000 = 10000(1.1)^3 – 10000 = 13310 – 10000 = 3310

Q.7 In how many different ways can the letters of the word ‘UNIVERSE’ be arranged?
Check Solution

Ans: C

The word ‘UNIVERSE’ has 8 letters. The letter ‘E’ appears twice. Therefore, the number of arrangements is 8!/2! = 40320/2 = 20160. However, this is not an option. Let’s consider the correct way to count: 8! = 40320 and since E appears twice, it would be 8!/2! = 20160. But the answer should be among the options. Since none of the options are 20160, there may be an error in the question or options. The closest one to this would be 10080

Q.8 The cost of 35 oranges and 45 apples is Rs. 460/-. What is the cost of 7 oranges and 9 apples?
Check Solution

Ans: A

The cost of 7 oranges and 9 apples is (1/5) of the cost of 35 oranges and 45 apples. Therefore, it is (1/5) * Rs. 460 = Rs. 92/-

Q.9 2 3 8 27 112 ?
Check Solution

Ans: A

The pattern is: (previous number * (n+1)) + n where n starts at 1. (2 * 1) + 1 = 3 (3 * 2) + 2 = 8 (8 * 3) + 3 = 27 (27 * 4) + 4 = 112 (112 * 5) + 5 = 565

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