Sutherland – Aptitude Questions & Answers for Placement Tests

Reviewing Previous Year Questions is a good start. Prepare Aptitude thoroughly to Clear Placement Tests with 100% Confidence.

Q.1 The ratio of milk and water in a mixture is 7:5. If 15 litres of water is added to the mixture, the ratio of milk and water becomes 7:8. Find the quantity of milk in the original mixture.

Check Solution

Ans: B

Let the original quantity of milk be 7x and water be 5x. After adding 15 litres of water: 7x / (5x + 15) = 7/8 56x = 35x + 105 21x = 105 x = 5 Therefore, the quantity of milk = 7x = 7 * 5 = 35 litres

Q.2 The ratio of the present ages of X and Y is 7:3. Ten years hence, the ratio of their ages will be 9:5. What is the difference between their present ages?

Check Solution

Ans: A

Let the present ages of X and Y be 7x and 3x respectively. After 10 years, their ages will be 7x+10 and 3x+10. According to the problem, (7x+10)/(3x+10) = 9/5. Solving this, 35x + 50 = 27x + 90. This gives 8x = 40, so x = 5. The present ages are 35 and 15. The difference is 35 – 15 = 20.

Q.3 A retailer marks up the price of a product by 60% above its cost price. He then offers a discount such that he still makes a profit of 28%. What is the percentage discount offered by the retailer?

Check Solution

Ans: A

Let the cost price be 100. Marked price = 100 + 60 = 160. Selling price = 100 + 28 = 128. Discount = 160 – 128 = 32. Discount percentage = (32/160) * 100 = 20%.

Q.4 P can complete a task in 20 days, Q can complete it in 30 days, and R can complete it in 60 days. They work together for 5 days. Then P and Q leave. How many days will R take to finish the remaining work?

Check Solution

Ans: D

Let the total work be the LCM of 20, 30, and 60, which is 60 units. P’s rate = 60/20 = 3 units/day, Q’s rate = 60/30 = 2 units/day, R’s rate = 60/60 = 1 unit/day. In 5 days, they complete 5 * (3+2+1) = 30 units. Remaining work = 60 – 30 = 30 units. R will take 30/1 = 30 days.

Q.5 A train crosses two bridges of lengths 200 meters and 300 meters in 10 seconds and 14 seconds respectively. What is the length of the train?

Check Solution

Ans: A

Let the length of the train be ‘x’ meters and the speed of the train be ‘s’ m/s. Then, (x + 200) / s = 10 and (x + 300) / s = 14. So, x + 300 = 1.4(x + 200). x + 300 = 1.4x + 280. 0.4x = 20. x = 50.

Q.6 (9756 – 3241 – 1500) / (200 + 100 + 50) = ?

Check Solution

Ans: B

(9756 – 3241 – 1500) = 5015, (200 + 100 + 50) = 350, 5015 / 350 = 14.32857… which is approximately 14.6

**Q.7 (27% of 8126) * (5.41% of 928) = ?**

Check Solution

Ans: A

(0.27 * 8126) * (0.0541 * 928) = 2194.02 * 50.2408 = 110054.48

Q.8 (105)2 / 11027 1/4 = ?

Check Solution

Ans: B

105 * 105 = 11025. 11025 / 11027 1/4 is approximately 1. 105 * 105 is 11025 and divided by 11025 will be approximately 1. Then you have to subtract 1/4. So the quotient is a little less than 1, but when you multiply this by 10 to get your answer, it will be close to 10.