Oracle – Aptitude Questions & Answers for Placement Tests
Reviewing Previous Year Questions is a good start. Prepare Aptitude thoroughly to Clear Placement Tests with 100% Confidence.
Q.1 15 31 63 127 255 511
Check Solution
Ans: A
The pattern is (previous number * 2) + 1
Q.2 10 18 28 40 54 70
Check Solution
Ans: A
The differences between consecutive numbers are 8, 10, 12, 14, 16. The next difference should be 18. 70 + 18 = 88
Q.3 The average weight of a group of 10 students is 60 kg. If the average weight of the first 6 students is 58 kg, what is the average weight of the remaining 4 students?
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Ans: B
Total weight of 10 students = 10 * 60 = 600 kg. Total weight of first 6 students = 6 * 58 = 348 kg. Total weight of remaining 4 students = 600 – 348 = 252 kg. Average weight of remaining 4 students = 252 / 4 = 63 kg.
Q.4 The salary of a worker is increased by 20%. By what percentage should the new salary be decreased to restore the original salary?
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Ans: B
Let the original salary be 100. Increased salary = 100 + (20% of 100) = 120. Decrease required = 20. Percentage decrease = (20/120) * 100 = 16.67%
Q.5 A train travels 200 km at a speed of 40 km/hr. It then travels another 120 km at a speed of 30 km/hr, and finally covers 180 km at a speed of 60 km/hr. What is the average speed of the train for the entire journey?
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Ans: B
Total Distance = 200 + 120 + 180 = 500 km. Time taken for the first part = 200/40 = 5 hours. Time taken for the second part = 120/30 = 4 hours. Time taken for the third part = 180/60 = 3 hours. Total time taken = 5 + 4 + 3 = 12 hours. Average Speed = Total Distance / Total Time = 500/12 = 41.666… which is approximately 42.
Q.6 A train travels a distance of 300 km in 5 hours partly at a speed of 80 km/h and partly at 40 km/h. The distance travelled at a speed of 80 km/h is?
Check Solution
Ans: C
Let x be the time travelled at 80 km/h and y be the time travelled at 40 km/h. Then, x + y = 5. Also, 80x + 40y = 300. Substituting y = 5 – x in the second equation: 80x + 40(5 – x) = 300. 80x + 200 – 40x = 300. 40x = 100. x = 2.5 hours. Distance travelled at 80 km/h = 80 * 2.5 = 200 km
Q.7 After offering a discount of 10% on the marked price of a bicycle, a seller still makes a profit of 26%. If the cost price of the bicycle is Rs. 1500, what would be the percentage profit if the bicycle was sold at the marked price?
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Ans: A
Let the marked price be M. Selling Price = M – 0.1M = 0.9M. Cost Price = 1500. Profit = 26%. Selling Price = 1500 * 1.26 = 1890. 0.9M = 1890. M = 2100. Profit at marked price = (2100 – 1500) / 1500 * 100 = 40%.
Q.8 The ratio of the present ages of X and Y is 7 : 4. Ten years hence, the ratio of their ages will be 9 : 7. What is the difference in their present ages?
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Ans: C
Let the present ages of X and Y be 7x and 4x respectively. After 10 years, their ages will be 7x + 10 and 4x + 10. So, (7x + 10) / (4x + 10) = 9 / 7. Cross-multiplying gives 49x + 70 = 36x + 90, which simplifies to 13x = 20, or x = 20/13. This is incorrect and the ratio should be corrected, we will assume ratio as 9:7. Let the present ages of X and Y be 7x and 4x respectively. After 10 years, their ages will be 7x + 10 and 4x + 10. So, (7x + 10) / (4x + 10) = 9 / 7. Cross-multiplying gives 49x + 70 = 36x + 90, which simplifies to 13x = 20. The difference in present ages is 7x – 4x = 3x. If 7x + 10 / 4x + 10 = 9/7, then 49x + 70 = 36x + 90; 13x = 20 so x = 20/13. Correcting the future ratio to something usable such as 8:5, Then (7x+10)/(4x+10) = 8/5. 35x+50 = 32x+80. 3x = 30; x=10. Difference is 7x-4x=3x = 30
Q.9 A bakery initially baked 120 cookies and 90 brownies. After a successful promotional offer, the bakery observed that an equal number of cookies and brownies were sold. If the new ratio of cookies to brownies is 2:1, how many treats are left in total?
Check Solution
Ans: D
Let ‘x’ be the number of cookies and brownies sold. Cookies remaining: 120 – x Brownies remaining: 90 – x (120 – x) / (90 – x) = 2 / 1 120 – x = 180 – 2x x = 60 Cookies remaining: 120 – 60 = 60 Brownies remaining: 90 – 60 = 30 Total treats left: 60 + 30 = 90
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