Nokia – Aptitude Questions & Answers for Placement Tests
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Q.1 Simple interest on Rs. 800 at 8 p.c.p.a. for ‘Y’ years is Rs. 192. What is the simple interest on Rs. ‘Y+500’ at the same rate of interest for 2 years?
Check Solution
Ans: D
First, find Y: SI = (P*R*T)/100 => 192 = (800 * 8 * Y)/100 => Y = 3. Now, find the SI for (3+500) = 503: SI = (503 * 8 * 2)/100 = 80.48. Since the options are integers, we check for any miscalculation. SI is approximately equal to 80.48. Given the options are far from this answer, the SI has to be found again. SI for Y + 500 for 2 years = (503*8*2)/100= 80.48 None of the answers match this number.
Q.2 A square and a triangle have the same perimeter. The sides of the triangle are 15 cm, 20 cm, and 25 cm. What will be the area of the square? (in cm2)
Check Solution
Ans: A
Perimeter of the triangle = 15 + 20 + 25 = 60 cm. Side of the square = 60 / 4 = 15 cm. Area of the square = 15 * 15 = 225 cm2.
Q.3 123 + 2345 + 34 + 45678 + 5 =?
Check Solution
Ans: A
123 + 2345 + 34 + 45678 + 5 = 48185
Q.4 7/9th of 459 + 2/7th of 224 = ?
Check Solution
Ans: C
(7/9) * 459 + (2/7) * 224 = 357 + 64 = 421
Q.5 4800 / 6 – 300 = ? / 4
Check Solution
Ans: B
(4800 / 6 – 300) * 4 = ? ; (800 – 300) * 4 = 500 * 4 = 2000. So, ? = 2000. None of the options is correct.
Q.6 The sum of the digits of a two-digit number is 9. When 9 is added to the number, the digits are reversed. What is the number?
Check Solution
Ans: D
Let the ten’s digit be x and the unit’s digit be y. The number is 10x + y. We have x + y = 9 and 10x + y + 9 = 10y + x. Simplifying the second equation gives 9x – 9y = -9, or x – y = -1. Solving the system of equations x + y = 9 and x – y = -1, we get x = 4 and y = 5. So the number is 45.
Q.7 The sum of the digits of a two-digit number is 9. If we subtract 27 from the number, the digits interchange their places. Find the number.
Check Solution
Ans: A
Let the ten’s digit be x and the unit’s digit be y. The number is 10x + y. We have x + y = 9. Also, 10x + y – 27 = 10y + x. Simplifying, we get 9x – 9y = 27, or x – y = 3. Adding the two equations x + y = 9 and x – y = 3, we get 2x = 12, so x = 6. Then, y = 9 – x = 9 – 6 = 3. The number is 63.
Q.8 A vessel contains a mixture of milk and water in the ratio of 7:5. When 15 litres of water is added to the mixture, the ratio of milk and water becomes 7:8. What is the initial quantity of the milk?
Check Solution
Ans: A
Let the initial quantity of milk and water be 7x and 5x respectively. After adding 15 litres of water, the ratio becomes 7:8. So, 7x/(5x+15) = 7/8. Cross-multiplying gives 56x = 35x + 105. This simplifies to 21x = 105, thus x = 5. Initial quantity of milk = 7x = 7*5 = 35 litres.
Q.9 The ratio of the ages of a father and son is 7:2. If the difference between their ages is 25 years, what will be the son’s age after 5 years?
Check Solution
Ans: B
Let the father’s age be 7x and the son’s age be 2x. Then, 7x – 2x = 25, so 5x = 25, and x = 5. The son’s current age is 2 * 5 = 10 years. After 5 years, his age will be 10 + 5 = 15 years.
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