Miracle Software Systems – Aptitude Questions & Answers for Placement Tests
Reviewing Previous Year Questions is a good start. Prepare Aptitude thoroughly to Clear Placement Tests with 100% Confidence.
Q.1 What is the simple interest earned on Rs 12,000 at 10% per annum for 5 years?
Check Solution
Ans: A
Simple Interest = (Principal * Rate * Time) / 100 = (12000 * 10 * 5) / 100 = 6000
Q.2 What should come in place of the question mark (?): 2, 6, 12, 20, ?, 42
Check Solution
Ans: B
The pattern is +4, +6, +8, +10, +12…
Q.3 The difference between a two-digit number and the number obtained by reversing its digits is 36. If the sum of the digits is 10, what is the original number?
Check Solution
Ans: A
Let the original number be 10x + y. Reversed number: 10y + x. (10x + y) – (10y + x) = 36 => 9x – 9y = 36 => x – y = 4. Also, x + y = 10. Adding the equations, 2x = 14 => x = 7. y = 3. Original number = 73.
Q.4 34.97% of 400.05 – 15.03% of 300.08 = ?
Check Solution
Ans: A
Approximately, (35/100)*400 – (15/100)*300 = 140 – 45 = 95
Q.5 15 × 864 ÷ 16 = ?
Check Solution
Ans: A
(15 × 864) / 16 = 12960 / 16 = 810
Q.6 12 carpenters can make 18 tables in 15 days. How many tables can 36 carpenters make in 30 days, assuming they work at the same rate?
Check Solution
Ans: B
Let T be tables made, C be carpenters, and D be days. We have the relation: T ∝ C * D. Therefore, T = k * C * D, where k is a constant. From the given information, 18 = k * 12 * 15. So, k = 18 / (12 * 15) = 1/10. Now, we want to find T when C = 36 and D = 30. T = (1/10) * 36 * 30 = 108
Q.7 The simple interest on a certain sum of money for 3 years at 10% p.a. is Rs. 900. What is the compound interest for the same sum, at the same rate, and for the same time period, compounded annually?
Check Solution
Ans: C
Principal = (Simple Interest * 100) / (Rate * Time) = (900 * 100) / (10 * 3) = Rs. 3000. Compound Interest = Principal * (1 + Rate/100)^Time – Principal = 3000 * (1 + 10/100)^3 – 3000 = 3000 * (1.1)^3 – 3000 = 3000 * 1.331 – 3000 = 3993 – 3000 = Rs. 993.
Q.8 The cost of 16 pens is Rs. 288/-. The cost of 12 pencils is Rs. 48/- and the cost of 10 erasers is Rs. 20/-. What is the total cost of 24 pens, 18 pencils and 15 erasers?
Check Solution
Ans: C
Cost of 1 pen = 288/16 = Rs. 18; Cost of 24 pens = 24 * 18 = Rs. 432; Cost of 1 pencil = 48/12 = Rs. 4; Cost of 18 pencils = 18 * 4 = Rs. 72; Cost of 1 eraser = 20/10 = Rs. 2; Cost of 15 erasers = 15 * 2 = Rs. 30. Total cost = 432 + 72 + 30 = Rs. 534/-
Q.9 The difference between 65% of a number and 40% of the same number is 210. What is 25% of that number?
Check Solution
Ans: B
Let the number be x. 0.65x – 0.40x = 210 0.25x = 210 x = 210 / 0.25 x = 840 Therefore, 25% of the number = 0.25 * 840 = 210
Q.10 In a competitive exam, a candidate needs to score 35% of the total marks to qualify. A student scored 280 marks and failed by 14 marks. What is the total marks of the exam?
Check Solution
Ans: C
Let the total marks be x. The qualifying marks are 280 + 14 = 294. Therefore, 0.35x = 294. Solving for x, x = 294/0.35 = 840.
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