MAQ Software – Aptitude Questions & Answers for Placement Tests

Ans: B

Let the two numbers be x and y. Given, x – y = 14 and (x + y)/6 = 8 Therefore, x + y = 48 Adding the two equations: 2x = 62 => x = 31 Substituting x in x – y = 14, we get 31 – y = 14 => y = 17

Ans: C

Divide 50 by 3, which is 16 with a remainder. The largest multiple of 3 less than or equal to 50 is 48 (3*16). So, there are 16 numbers.

Ans: A

Let the number be x. Then x/7 = x – 12. Multiplying both sides by 7 gives x = 7x – 84. So, 6x = 84, which means x = 14.

Ans: D

The minute hand moves 360 degrees in 60 minutes (3600 seconds). Therefore, in 36 seconds, it moves (36/3600) * 360 = 3.6 degrees.

Ans: B

³√0.027 = ³√(27/1000) = 3/10 = 0.3

Ans: B

Total weight of 5 friends = 5 * 60 = 300 kg. After one friend leaves, total weight = 300 – 70 = 230 kg. New average weight = 230 / 4 = 57.5 kg, which is approximately 58 kg.

Ans: A

Since PR = RS, triangle PRS is isosceles with ∠RPS = ∠PSR. Also, since QS bisects ∠PQR, ∠PQS = ∠RQS. Arc PS subtends ∠PQS and ∠PRS, therefore ∠PRS = 2∠PQS. Since ∠QPR = φ and ∠RPS = ∠PSR, ∠PRS = 180 – φ – ∠PSR = 180 – φ – ∠RPS. Since sum of angles in a triangle is 180, 2∠PQS + φ + ∠RPS = 180. Since ∠PRS = 2∠PQS, therefore ∠QRS = ∠PRS – ∠QRP and as PR = RS, we can deduce that ∠RQS = ∠RPS. Therefore, in triangle PQR, since ∠QPR = φ, then ∠QRP = (180 – ∠PQR – φ) and ∠PQR = 2 * ∠RQS = 2∠RPS. Therefore ∠QRS = ∠PRS – ∠QRP = 2∠PQS – (180 – ∠PQR – φ). Hence ∠QRS= φ