JP Morgan – Aptitude Questions & Answers for Placement Tests

Ans: B

X’s one day work = 1/15, Y’s one day work = 1/20. Work done by X and Y in 6 days = 6(1/15 + 1/20) = 6(7/60) = 7/10. Remaining work = 1 – 7/10 = 3/10. Let Y worked alone for ‘n’ days. In 8 days, work done by Y and Z = 3/10. So, 8(Y’s one day work + Z’s one day work) = 3/10. Y’s one day work = 1/20, Z’s one day work = 1/60. 8(1/20 + 1/60) = 8(4/120) = 8(1/30) = 4/15. Let the remaining work be completed by Y and Z in 8 days, where the work done by Y + Z in 8 days is 3/10. Then (3/10) – 8/60 = 3/10 – 2/15 = (9-4)/30 = 5/30 = 1/6. So, 1/6 of work is done by Y alone. Hence, the number of days Y worked alone is 4.

Ans: A

We know that the product of two numbers is equal to the product of their HCF and LCM. Let the other number be x. So, 45 * x = 15 * 180 => x = (15 * 180) / 45 = 60

Ans: B

Let the usual speed be s and the usual time be t. Then the distance is st. When the speed is (3/4)s, the time taken is t + 50. So, (3/4)s(t + 50) = st. This simplifies to 3st + 150s = 4st, or st = 150s. Therefore, t = 150 minutes.

Ans: B

(1/2 + 1/3) = 5/6 and (1/4 + 1/6) = 5/12. (5/6) / (5/12) = (5/6) * (12/5) = 2

Ans: C

Let the cost price be x. Loss % = x%. Loss = x/100 * x. Selling Price = Cost Price – Loss. 75 = x – x^2/100. x^2 – 100x + 7500 = 0. Using the quadratic formula, x = 50 + sqrt(2500 – 7500). This results in complex numbers. Try the options: If CP = 100, Loss % = 100, Loss = 100. SP = 0. If CP = 150, Loss% = 150. SP < 0. Using the equation, SP = x - (x*x/100) 75=x-(x^2/100) If x=50 then 75 = 50-(2500/100), 75=50-25 not possible. The root is likely incorrect. Let's analyze with options. If CP is 100, then loss is 100 percent meaning the man will lose 100 on the watch thus not matching the given scenario. If CP=50, loss% should also be 50. Loss=50*50/100=25, which means SP is 50-25=25 not 75. However, if we consider quadratic equations, (x^2/100)-x+75=0. Thus x=50+50sqrt(1-3). so neither answers are correct. The question itself contains an error. Assuming the loss % is the same as cost price and that there are no options matching, we can assume that if x=50. Then the loss is 25 as per the question, SP is 25, not 75. However if cost price equals 100, loss equals 100%, sp becomes zero. This leads to options that don't satisfy the equation 75 = x - (x * x) / 100

Ans: B

Let the selling price be 100. Then profit is 20. Cost price = Selling price – Profit = 100-20 = 80. Profit % on cost price = (Profit/Cost price) * 100 = (20/80) * 100 = 25%.

Ans: B

Let the present ages of the father and son be 7x and 2x respectively. After 5 years, their ages will be 7x+5 and 2x+5. According to the problem, (7x+5)/(2x+5) = 8/3. Cross-multiplying, 3(7x+5) = 8(2x+5). 21x+15 = 16x+40. 5x = 25. x=5. Therefore, the father’s present age is 7x = 7*5 = 35 years.