Ittiam – Aptitude Questions & Answers for Placement Tests

Ans: B

SI = (P * R * T) / 100. SI for each year is calculated, then added up. Year 1: SI = (12000 * 10 * 1) / 100 = 1200 Year 2: SI = (12000 * 12 * 1) / 100 = 1440 Year 3: SI = (12000 * 15 * 1) / 100 = 1800 Total SI = 1200 + 1440 + 1800 = 4440

Ans: A

Total weight of the initial group = 10 * 40 = 400 kg. The total weight of the group after replacement = 10 * 42 = 420 kg. The new student weighs 45 kg. Let the replaced student weigh x kg. Therefore, 400 – x + 45 = 420. Simplifying, x = 25 kg.

Ans: B

Let ‘x’ be the initial number of friends. The original contribution per friend was 1200/x. When 4 friends backed out, the number of friends became x-4, and the contribution per friend became 1200/(x-4). We are given that 1200/(x-4) = 1200/x + 15. Multiplying by x(x-4) gives 1200x = 1200(x-4) + 15x(x-4). Simplifying, we get 0 = -4800 + 15x^2 – 60x. Dividing by 15, we get x^2 – 4x – 320 = 0. Factoring, (x-20)(x+16) = 0. Thus, x=20 or x=-16. Since the number of friends cannot be negative, x=20.

Ans: B

Let the distance between A and B be ‘d’ km. Time taken to travel from A to B = d/60 hours. Time taken to travel from B to A = d/40 hours. Total time = d/60 + d/40 = 10. (2d + 3d)/120 = 10. 5d = 1200. d = 240 km.

Ans: B

Let the total work be W. Then, 12 typists * 18 days = W. So, 1 typist * 1 day = W / (12 * 18). Let x be the number of typists required to complete the work in 12 days. Then, x * 12 = W x * 12 = 12 * 18 x = (12 * 18) / 12 x = 18 Number of extra typists = 18 – 12 = 6

Ans: A

Let the speed of the boat in still water be ‘b’ and the speed of the stream be ‘s’. Upstream speed = b – s = 24/6 = 4 kmph Downstream speed = b + s = 24/4 = 6 kmph Adding the two equations: 2b = 10, so b = 5 kmph Substituting b = 5 in b + s = 6, we get s = 1 kmph

Ans: B

Let Y’s efficiency be 100 units/day. Then X’s efficiency is 80 units/day. Y’s work in 25 days = 25 * 100 = 2500 units. Combined efficiency = 100 + 80 = 180 units/day. Days taken by X and Y together = 2500/180 = 125/9

Ans: C

Let the original number be 10x + y. We have |x – y| = 3. Reversing the digits gives 10y + x. 10y + x = 2(10x + y) – 9. Simplifying, 10y + x = 20x + 2y – 9 => 19x – 8y = 9. Also, either x – y = 3 or y – x = 3. If x – y = 3, then x = y + 3. Substitute in 19x – 8y = 9 => 19(y+3) – 8y = 9 => 11y = -48 (not possible). If y – x = 3, then y = x+3. Substitute in 19x – 8y = 9 => 19x – 8(x+3) = 9 => 11x = 33 => x = 3, y = 6. So, original number = 36. However, this is not an option. Checking the given options. If the original number is 74, and the reversed number is 47. 2(74) – 9 = 148 – 9 = 139, not 47. If the original number is 63, and reversed number is 36. 2(63) – 9 = 126-9 = 117, not 36. Check 41. Reversed is 14. 2(41) – 9 = 82-9 = 73. So its likely a simple error, but closest value that matches difference of 3 and condition is option C.

Ans: A

Time taken for the first 200 km = 200/40 = 5 hours. Time taken for the next 240 km = 240/60 = 4 hours. Total distance = 200 + 240 = 440 km. Total time = 5 + 4 = 9 hours. Average speed = Total distance / Total time = 440/9 = 48.88 km/hr (approximately).

Ans: D

Ratio of investments: (40000*6) : (50000*8) : (60000*5) = 24:40:30 = 12:20:15. Z’s share = (15/47) * 26400 = 8400. There seems to be a calculation error in the provided options, but the closest is D.