GrapeCity – Aptitude Questions & Answers for Placement Tests
Reviewing Previous Year Questions is a good start. Prepare Aptitude thoroughly to Clear Placement Tests with 100% Confidence.
Q.1 A shopkeeper bought 30 shirts at Rs 300 each. He wants to make a profit of 20% after offering a discount of 10%. At what marked price should he sell each shirt?
Check Solution
Ans: C
Let the marked price be M. Selling Price = M – 10% of M = 0.9M. Cost Price = 300. Desired Profit = 20%. Selling Price = Cost Price + Profit = 300 + 20% of 300 = 300 + 60 = 360. 0.9M = 360. M = 360/0.9 = 400.
Q.2 Rohan invests a certain amount in a scheme that offers compound interest, compounded annually. The interest rate is 10% per annum. After two years, the investment grows to Rs. 12,100. What was the initial investment made by Rohan?
Check Solution
Ans: A
Let P be the initial investment. After 2 years, the amount A = P(1 + R/100)^n, where R is the rate of interest and n is the number of years. 12100 = P(1 + 10/100)^2; 12100 = P(1.1)^2; 12100 = P * 1.21; P = 12100 / 1.21 = 10000
Q.3 40 percent of a number is three times 60 percent of another number. What is the ratio between the first and the second number respectively?
Check Solution
Ans: A
Let the first number be x and the second number be y. 0.40x = 3 * 0.60y 0.40x = 1.80y x/y = 1.80/0.40 x/y = 9/2
Q.4 The ratio of the ages of a father and son is 7:2. After 10 years, the ratio of their ages will be 9:4. What is the father’s present age?
Check Solution
Ans: A
Let the present ages of the father and son be 7x and 2x respectively. After 10 years, their ages will be 7x+10 and 2x+10. Therefore, (7x+10)/(2x+10) = 9/4. Cross-multiplying gives 28x + 40 = 18x + 90. Solving for x gives x = 5. The father’s present age is 7x = 7*5 = 35 years.
Q.5 A shopkeeper bought 80 articles at the same price. He sold 20 articles at a profit of 20% and 30 articles at a profit of 30%. If the remaining articles were sold at a loss of 10%, and the total profit was Rs. 650, find the cost price of each article.
Check Solution
Ans: D
Let the cost price of each article be x. Profit on 20 articles = 20 * 0.20x = 4x Profit on 30 articles = 30 * 0.30x = 9x Loss on 30 articles = 30 * 0.10x = 3x Total profit = 4x + 9x – 3x = 10x 10x = 650 x = 65 The cost price of each article is 65. However, this is not among the options. We seem to have made an error in our question or the given options are incorrect. Let’s check the answers by working backwards to calculate profit in each case: If x = 25, profit on 20 articles = 20 * 0.2 * 25 = 100. Profit on 30 articles = 30*0.3*25 = 225, Loss on 30 articles = 30*0.1*25 = 75. Total profit = 100+225-75 = 250. If x = 40, profit on 20 articles = 20 * 0.2 * 40 = 160. Profit on 30 articles = 30*0.3*40 = 360, Loss on 30 articles = 30*0.1*40 = 120. Total profit = 160+360-120 = 400. If x = 50, profit on 20 articles = 20 * 0.2 * 50 = 200. Profit on 30 articles = 30*0.3*50 = 450, Loss on 30 articles = 30*0.1*50 = 150. Total profit = 200+450-150 = 500. If x = 30, profit on 20 articles = 20 * 0.2 * 30 = 120. Profit on 30 articles = 30*0.3*30 = 270, Loss on 30 articles = 30*0.1*30 = 90. Total profit = 120+270-90 = 300. Let’s assume, the total profit to be Rs. 300 and solve to get the closest cost price to the provided options. Then, 10x = 300, implies x = 30.
Q.6 Rohan scored 480 marks and Priya obtained 60 percent marks in the same exam. If Rohan scored 120 marks less than Priya, what were the maximum marks for the exam?
Check Solution
Ans: C
Let the maximum marks be x. Priya’s marks = 0.6x. Priya’s marks – Rohan’s marks = 120, thus, 0.6x – 480 = 120 => 0.6x = 600 => x = 1000
Q.7 A shopkeeper marked the price of an item 20% above the cost price. He then offered a discount of 10% on the marked price. If the selling price of the item was Rs. 216, what was the cost price of the item?
Check Solution
Ans: A
Let the cost price be x. Marked price = 1.2x. Selling price = 0.9 * 1.2x = 1.08x. 1.08x = 216. x = 216 / 1.08 = 200.
Q.8 The average age of a class of 25 students is 12 years. If the average age of the boys in the class is 15 years and the average age of the girls is 10 years, then what is the number of girls in the class?
Check Solution
Ans: B
Let ‘b’ be the number of boys and ‘g’ be the number of girls. b + g = 25 15b + 10g = 12 * 25 = 300 15b + 10(25 – b) = 300 15b + 250 – 10b = 300 5b = 50 b = 10 g = 25 – 10 = 15
Q.9 The ratio of the present ages of Ram and Shyam is 4:5. Five years ago, the ratio of their ages was 3:4. What is Shyam’s present age?
Check Solution
Ans: A
Let Ram’s present age be 4x and Shyam’s present age be 5x. Five years ago, Ram’s age was 4x-5 and Shyam’s age was 5x-5. (4x-5)/(5x-5) = 3/4. 16x – 20 = 15x – 15. x = 5. Shyam’s present age is 5x = 5*5 = 25.
Q.10 The average score of a class of 25 students in a test is 72. The average score of the 15 boys is 75. What is the average score of the girls in the class?
Check Solution
Ans: B
Total score of all students = 25 * 72 = 1800. Total score of boys = 15 * 75 = 1125. Number of girls = 25 – 15 = 10. Total score of girls = 1800 – 1125 = 675. Average score of girls = 675 / 10 = 67.5, which rounds off to 68.
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