GE – Aptitude Questions & Answers for Placement Tests
Reviewing Previous Year Questions is a good start. Prepare Aptitude thoroughly to Clear Placement Tests with 100% Confidence.
Q.1 A box contains 4 green, 6 yellow, and 5 purple marbles. If three marbles are selected at random, what is the probability that all three marbles are of the same color?
Check Solution
Ans: B
Calculate the probability for each color and sum them. Green: (4C3) / (15C3) = 4/455 Yellow: (6C3) / (15C3) = 20/455 Purple: (5C3) / (15C3) = 10/455 Total probability: (4 + 20 + 10) / 455 = 34/455. But this is not an option. Let’s check the options again: Green: 4C3 / 15C3 = 4/455 Yellow: 6C3 / 15C3 = 20/455 Purple: 5C3 / 15C3 = 10/455 Total probability is (4+20+10)/455 = 34/455. There seems to be an error in provided options. Let’s try the nearest answer if we choose to use only the yellow and purple as they have more items. Then we will have (20+10)/455=30/455=6/91. Now let’s use the provided options to see where’s the problem. Let’s assume we made a mistake and we have to compute the probability that exactly two are of same color: (4C2 * 11C1 + 6C2 * 9C1 + 5C2 * 10C1)/15C3 = (264+540+450)/455 is incorrect. The options seems wrong. Let’s recalculate based on given options: (4C3+6C3+5C3)/15C3=(4+20+10)/455 = 34/455, but options provided are incorrect. So, if none of the option can be used.
Q.2 A bag contains 4 white, 6 green and 5 yellow marbles. If three marbles are drawn at random, what is the probability that all three are of different colors?
Check Solution
Ans: B
Total number of marbles = 4 + 6 + 5 = 15. Total number of ways to draw 3 marbles = 15C3 = (15*14*13)/(3*2*1) = 455. Number of ways to draw one white, one green, and one yellow marble = 4C1 * 6C1 * 5C1 = 4 * 6 * 5 = 120. Probability = 120/455 = 24/91
Q.3 What should come in place of the question mark (?) in the following number series? 5 11 23 ? 95 191
Check Solution
Ans: A
The pattern is: (previous number * 2) + 1. 5*2 + 1 = 11 11*2 + 1 = 23 23*2 + 1 = 47 47*2 + 1 = 95 95*2 + 1 = 191
Q.4 A train travels a certain distance at a speed of 60 kmph. If it increases its speed by 10 kmph, it takes 1 hour less to cover the same distance. What is the original distance covered by the train?
Check Solution
Ans: A
Let the distance be ‘d’ km and the original time taken be ‘t’ hours. Then, d = 60t —(1) Also, d = (60+10)(t-1) = 70(t-1) —(2) Equating (1) and (2), 60t = 70t – 70 10t = 70 t = 7 hours Therefore, d = 60 * 7 = 420 km
Q.5 A farmer invests in a well. The well generates annual profits of Rs. 5000. If the farmer paid 25 times the annual profit for the well, what is the percentage return on his investment?
Check Solution
Ans: B
The farmer invested 25 * Rs. 5000 = Rs. 125000. The return is Rs. 5000. Percentage return = (Return / Investment) * 100 = (5000/125000) * 100 = 4%
Q.6 Rohan’s income is first increased by 20% and then decreased by 20%. What is the percentage change in his income?
Check Solution
Ans: B
Let Rohan’s initial income be 100. After increasing by 20%, it becomes 100 + 20 = 120. Then, decreasing by 20%, it becomes 120 – (20% of 120) = 120 – 24 = 96. The change is 100 – 96 = 4, which is a decrease of 4%.
Q.7 A train leaves Delhi for Mumbai at 6:00 AM, traveling at 70 kmph. Another train leaves Mumbai for Delhi at 7:00 AM, traveling at 80 kmph. The distance between Delhi and Mumbai is 1000 km. At what time will the two trains meet?
Check Solution
Ans: C
In the first hour, the first train travels 70 km. Remaining distance = 1000 – 70 = 930 km. Relative speed = 70 + 80 = 150 kmph. Time to meet = 930/150 = 6.2 hours. 6.2 hours is equal to 6 hours and 12 minutes. The second train leaves at 7:00 AM. Therefore, they will meet at 7:00 AM + 6 hours and 12 minutes, which is approximately 1:12 PM.
Q.8 A dishonest dealer professes to sell his goods at cost price, but he uses a weight of 900 grams for a kilogram. Find his gain percent.
Check Solution
Ans: B
Let the cost price of 1 gram be Re 1. Then, the cost price of 1000 grams (1 kg) = Rs. 1000. The dealer sells 900 grams for Rs. 1000. So, profit = 1000 – 900 = 100. Gain% = (Profit/CP) * 100 = (100/900) * 100 = 11.11%
Q.9 In a school election, the winning candidate secured 60% of the votes and defeated their opponent by 480 votes. What was the total number of votes cast?
Check Solution
Ans: C
Let the total votes be x. The winning candidate got 0.6x votes and the losing candidate got 0.4x votes. The difference in votes is 0.6x – 0.4x = 0.2x, which is equal to 480. So, 0.2x = 480, and x = 480/0.2 = 2400.
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