CGI – Aptitude Questions & Answers for Placement Tests

Ans: A

Let the cost price be CP and the selling price be SP. Gross profit = 20% of CP, so Profit = 0.2CP. Selling Price = Cost Price + Profit, so SP = CP + 0.2CP = 1.2CP. 40% of SP = 0.4SP = 0.4 * 1.2CP = 0.48CP. Therefore, 40% of SP is 48% of CP.

Ans: A

Let the initial price be P and the initial sales be S. Initial revenue = P*S. New price = 1.2P. New sales = 0.9S. New revenue = 1.2P * 0.9S = 1.08PS. Change in revenue = 1.08PS – PS = 0.08PS. Percentage change = (0.08PS / PS) * 100 = 8%.

Ans: A

David’s annual salary is $42,000. Since the ratio of John’s salary to David’s salary is 5:7, we can calculate John’s annual salary: (5/7) *$42,000 = $30,000. To find John’s monthly salary, divide his annual salary by 12:$30,000 / 12 = $2,500

Ans: A

Let Alex’s current age be 5x and Ben’s current age be 3x. Ten years ago, Alex’s age was 5x – 10 and Ben’s age was 3x – 10. According to the problem, (5x – 10) / (3x – 10) = 3/1. Solving this gives 5x – 10 = 9x – 30, so 4x = 20 and x = 5. Ben’s current age is 3x = 3 * 5 = 15.

Ans: A

Let the cost price of the first article be x. Then, the cost price of the second article is 1000 – x. Selling price of the first article = x + 0.2x = 1.2x Selling price of the second article = (1000 – x) – 0.1(1000 – x) = 0.9(1000 – x) Total selling price = 1.2x + 0.9(1000 – x) Profit = Total selling price – Total cost price 20 = 1.2x + 900 – 0.9x – 1000 20 = 0.3x – 100 120 = 0.3x x = 400

Ans: A

A’s investment = 5000 * 12 = 60000. B’s investment = 6000 * 4 + 5000 * 8 = 24000 + 40000 = 64000. C’s investment = 7000 * 6 + 5000 * 6 = 42000 + 30000 = 72000. Ratio of profits A:B:C = 60000:64000:72000 = 15:16:18. C’s share = (18/49) * 1950 = 718.36 (approx). The closest value is Rs. 700, but calculating exactly is tough. A more appropriate prompt will give an exact answer as one of the options. Let’s solve this with the option values and derive the profit share for the available options. If C gets 700, the ratio is (700/1950) = 14/39. 72000/total = 14/39, total = (72000*39)/14=200571 (approx). This is not correct. To solve exactly, calculate A’s share as 15/49 * 1950 = 597.95. B’s Share = 16/49 * 1950 = 636.73. C’s share = 18/49 * 1950 = 718.36, which is approx 700.

Ans: A

Let the speed of the boat in still water be ‘x’ km/hr. Downstream speed = (x + 3) km/hr. Upstream speed = (x – 3) km/hr. Distance AB = 3(x + 3) = 5(x – 3) 3x + 9 = 5x – 15 2x = 24 x = 12

Ans: A

Let the speed of Y be 5v. Then the speed of X is 7v. Let the time taken by both to finish be t. Distance covered by X = 7v*t and distance covered by Y = 5v*t + 60. Since they reach at the same time, distance covered by X is the same as distance covered by Y. Thus, 7vt = 5vt + 60. Therefore, 2vt = 60 or vt = 30. The total distance is 7vt = 7*30 = 210.

Ans: C

Let the original speed be ‘s’ km/hr and the distance be ‘d’ km. Then, d = 10s. Also, d = (s – 5) * 12. Therefore, 10s = 12(s – 5). 10s = 12s – 60. 2s = 60. s = 30.