Bosch – Aptitude Questions & Answers for Placement Tests

Ans: C

Since x > 2, 3x > 6. Since y < -3, 2y < -6. Therefore, 3x + 2y could be positive, negative, or zero. 5x > 10 and 4y < -12, so 5x > 4y. Since y is negative, -y is positive. x > 2 and -y is positive. Therefore, x could be less than, equal to, or greater than -y.

Ans: A

Let the work done by a worker in a day be W and the work done by a child in a day be C. 15W * (D/4) = 1 (Total work) => W = 4/(15D) 10C * (D/5) = 1 (Total work) => C = 1/(2D) When they work together: Total work done in a day = 15W + 10C = 15*(4/(15D)) + 10*(1/(2D)) = 4/D + 5/D = 9/D Days to complete the work = 1/(9/D) = D/9

Ans: A

Volume of a sphere = (4/3)πr^3 = (4/3)π(6)^3 = (4/3)π(216) = 288π

Ans: B

Let the two numbers be x and y. We have x^2 – y^2 = 45 and x – y = 3. Since x^2 – y^2 = (x – y)(x + y), we can substitute the given values: 45 = 3 * (x + y). Dividing both sides by 3, we get x + y = 15.

Ans: A

The question likely refers to a bitwise AND operation. 25 in binary is 11001, and 15 in binary is 01111. Performing a bitwise AND operation (11001 & 01111) results in 01001, which is 9 in decimal. However, the options provided do not include the result. It is also possible that the question implies addition. (25 + 15 = 40) or subtraction or finding common factors. Considering the available answer choices, if we treat it as finding the greatest common factor (GCF) of the two numbers it is 5, this value is not provided as an option so the intention of the question cannot be clearly identified. The only option available is either addition or a trick question with an unrelated option.

Ans: C

X’s investment was for 12 months, and Y’s investment was for 8 months. Ratio of their profits = (30000 * 12) : (45000 * 8) = 360000 : 360000 = 1 : 1. Thus Y’s share = (1/2) * 16000 = 8000.

Ans: C

Let ‘x’ be the amount of pure acid added. The initial amount of acid is 40 * 0.15 = 6 liters. After adding ‘x’ liters of pure acid, the total volume becomes 40 + x liters, and the total amount of acid is 6 + x liters. The concentration becomes (6 + x) / (40 + x) = 0.30. Solving for x: 6 + x = 12 + 0.3x => 0.7x = 6 => x = 6/0.7 = 8.57. Thus approximately 8 liters.

Ans: B

Let the original number of workers be ‘w’ and the total work be ‘W’. The work done by ‘w’ workers in 12 days is W. So, w * 12 = W. If the number of workers is doubled to 2w, let ‘d’ be the number of days to complete the same work W. Then, 2w * d = W. Since w * 12 = W, substituting W in the second equation, 2w * d = w * 12. Dividing both sides by 2w, d = 6.

Ans: A

Relative speed = 60 + 90 = 150 km/hr. Time to meet = 600 / 150 = 4 hours. Distance from A = 60 * 4 = 240 km.

Ans: A

The ratio of their investments is (8000*4) : (6000*6) : (5000*8) = 32 : 36 : 40 = 8 : 9 : 10. R’s share = (10/27) * 9300 = 3444.44 approximately. There might be an error in the question. Checking with the nearest option as none of the option satisfies the calculation. Rechecking, we have 8+9+10 = 27 total shares. Share of R = (10/27)*9300 = 3444.44

Ans: A

A’s one day work = 1/10, B’s one day work = 1/15, C’s one day work = 1/20. (A+B)’s 3 days work = 3*(1/10 + 1/15) = 3*(1/6) = 1/2. Remaining work = 1 – 1/2 = 1/2. (B+C)’s 4 days work = 4*(1/15+1/20) = 4*(7/60) = 7/15. Remaining work = 1/2 – 7/15 = (15-14)/30 = 1/30. B’s one day work = 1/15. Therefore days required = (1/30)/(1/15) = 1/2. Hence the answer is not in the options.

Ans: C

Apples remaining = 80 * (1 – 0.20) = 64. Oranges remaining = 120 * (1 – 0.25) = 90. Total fruits remaining = 64 + 90 = 154. Percentage of apples = (64 / 154) * 100 = 41.55% which is closest to 40%.

Ans: C

Since David > Sarah and Sarah > Michael, David earns the most.

Ans: D

The information provided creates a contradiction: David > Mark, Susan > Mark, and Susan > David. But also, David > Susan. This leads to a circular and inconsistent relationship.

Ans: A

We can deduce the order from the information provided. C is ahead of A, who is ahead of B. E is ahead of D, and E is behind B. Combining these gives the order: C, A, B, E, D.

Ans: D

C < A < B < E < D

Ans: B

We can deduce the race order. C > A > B. Also, E > D > B. Combining, we have C > A > B and E > D > B. Since C must come before A and E must come before D, the full order is C > A > E > D > B. Therefore, B finished last.

Ans: B

Each letter in the original word is shifted one position forward in the alphabet. R becomes S, E becomes F, A becomes B, S becomes T, O becomes P, and N becomes O. Applying this same logic to THINKING: T becomes U, H becomes J, I becomes M, N becomes L, K becomes J, I becomes O, N becomes H, and G becomes. Therefore, THINKING becomes UJMLJOH.