Bank Exams Challenge #2

A certain number of persons are sitting in a row facing north. Three persons sit between A and B. C sits second to the right of B. D sits fifth to the left of C. Two persons sit between D and E. The number of persons sit between D and C is one more than the number of persons sit between D and F. No one sits to the left of F. The position of A with respect to F is same as the position of C with respect to G. As many persons sit to the left of F as to the right of C.

Eight persons A, B, C, D, E, F, G and H are members of a three-generation family, with no single parent. G is the daughter-in-law of D. B has no daughter. H is the aunt of A. G is the sister-in-law of C. C is married member of the family. B is the grandfather of A. C and A are of opposite gender. E is the brother of F and has no child

Six persons – A, B, C, D, E and F – were born in different months – April, July, and September – on two different dates, i.e., 9th and 26th of the same year. Each person likes a different colour – Red, Blue, Pink, Green, White, and Yellow. All the information is not necessarily used in the same order
Two persons were born between F and the person who likes red. D was born immediately before F on an odd date and in the month having even number of days. The one who likes pink was born two persons  before C. E was born immediately before C on an even date. Two persons were born between the ones who like pink and blue. A was born before the one who likes green and two persons after the one who
likes yellow. E doesn’t like yellow.

Statements:
Only a few club is court
Some court is allow
No allow is revenue
Conclusions:
I. Some club being allow is a possibility
II. Some court are not revenue.

Seven persons A, B, C, D, E, F and G were born on seven different years i.e., 1947, 1959, 1964, 1973, 1978, 1988 and 2001 on the same month and same date. (Base year is considered as 2025 for age calculation). The sum of the ages of C and F is equal to the age of D. G’s age is divisible by 6. The total age of A and G is a prime number. A is just older than F. The sum of the age of B and A is divisible by 5.

Statements: O > S = G ≤ R ≥ K; L ≤ R =P; T < J = P
Conclusions:
I. S < L
II. J ≥ G

Six persons – A, B, C, D, E and F – bought six different types of cars – Sedan, SUV, Hatchback, Limousine, Coupe, and Convertible – one after the other, but not necessarily in the same order. The one who bought Sedan purchased it three persons before F. As many persons bought car before F as after the one who purchased Hatchback. Two persons bought cars between the ones who purchased Hatchback and SUV. E bought the car before the one who purchased SUV but immediately before A.
Coupe was bought two persons after A but immediately bought before convertible. Convertible was bought before B but after D.